Question

在书店应用程序中，我有一个表单，用于添加由Book编写的Author和属于Shelf的{{1}}。书需要与书架相关联。

Bookstore

我的问题是：实际上有更简洁的方式来写这个吗？我很确定有，但我在某处错过了。

Answer 1

试一试

class AddFruitForm(forms.Form):

    def save(self, request):       
        # list all your fields here
        fields_expected = ['fruit_name', 'fruit_color', ...]

        # this should give you the dict with all the fields equal to "None" 
        fields = dict.fromkeys(fields_expected)     

        # this relace the None value with the good data from cleaned_data
        fields.update(self.cleaned_data)

        # assign all the in the dict to the model, key=value
        fruit = Fruit(**fields)
        fruit.save(force_insert=True, force_update=False)

但是，如果您的模型可以为这些值接受None，则不必如上所述明确提供给模型，您可以改为使用模型来处理默认值。

class AddFruitForm(forms.Form):

    def save(self, request):       
        fields = self.cleaned_data
        fields['my_custom_field'] = 'some data not from the field'

        fruit = Fruit(**fields)
        fruit.save(force_insert=True, force_update=False)

Answer 2

如果您的数据与模型相关联，则最好使用ModelForm。您可以在前端拥有任意数量的表单并完全提交。代码非常简单：

# models.py
class BookForm(forms.ModelForm):
    class meta:
        model = Book

class Shelf(forms.ModelForm):
    class meta:
        model = Shelf

# views.py
def addbook(request):
    book_form = BookForm(request.POST or None)
    shelf_form = SelfForm(request.POST or None)
    if book_form.is_valid() and shelf_form.is_valid():
        book = book_form.save()
        shelf = shelf_form.save()
        return redirect('some-list-view')

    return render(request, 
                  'addbook.html', 
                  {'book_form': book_form, 'shelf_form': shelf_form})

# addbook.html
<form action="/addbook/" method="post">
    {% csrf_token %}
    {{ book_form }}
    {{ shelf_form }}
    <input type="submit" value="Submit" />
</form>

使用save（）方法处理Django上的表单数据的简洁方法

2 个答案: