Question

我有一个打开弹出窗口的按钮：

<button onclick="loadUsers()">User Accounts</button><br>

loadUsers代码在这里：

    function loadUsers()
    {
        userWindow = window.open("", "_blank", "toolbar=yes,scrollbars=yes,resizable=yes,top=0,left=0,width=900,height=405");
        userWindow.document.write("<html><head><link rel='stylesheet'type='text/css' href='css/main.css'><title>Account Management</title></head><body><div class='popup'><?php loadUsersIntoTable(); ?></div></body></html>");
    }

正如您所看到的，该文档调用了一个PHP函数loadUsersIntoTable，该函数连接到数据库并检索用户列表，然后将其全部放入表中：

//Preloaded function in PHP, will be called later on
        function loadUsersIntoTable()
        {

            require "db.inc";

            //Store the connection in a variable for later use
            $conn = mysqli_connect($hostname, $username, $password, $dbname);

            //Check for connection
            if(!$conn ){
                die('Could not connect: ' . mysqli_connect_error());
            }

            //Define query variable
            $query = "SELECT * FROM users";

            //Start the query
            if($result=mysqli_query($conn,$query))
            {

                //Create our HTML table start here
                echo("<center><table border='1' width='100%'>");
                    echo("<tr>");
                    echo("<th bgcolor='#BABABA'>ID</th>");
                    echo("<th bgcolor='#BABABA'>Name</th>");
                    echo("<th bgcolor='#BABABA'>Telephone</th>");
                    echo("<th bgcolor='#BABABA'>DoB</th>");
                    echo("<th bgcolor='#BABABA'>Address</th>");
                    echo("<th bgcolor='#BABABA'>Country</th>");
                    echo("<th bgcolor='#BABABA'>State</th>");
                    echo("<th bgcolor='#BABABA'>Postcode</th>");
                    echo("<th bgcolor='#BABABA'>Manage</th>");
                    echo("</tr>");

                    while($row = mysqli_fetch_array($result))
                    {

                        //Define all variables we will use
                        $id = $row['ID'];
                        $name = $row['Name'];
                        $telnumber = $row['Tel'];
                        $age = $row['DoB'];
                        $address1 = $row['Address'];
                        $country = $row['Country'];
                        $state = $row['State'];
                        $postcode = $row['Postcode'];

                        echo("<tr>");
                            echo("<td>$id </td>");
                            echo("<td>$name </td>");
                            echo("<td>$telnumber </td>");
                            echo("<td>$age </td>");
                            echo("<td>$address1 </td>");
                            echo("<td>$country </td>");
                            echo("<td>$state </td>");
                            echo("<td>$postcode </td>");
                            echo("<td><form method='POST' ACTION='process_deleteuser.php?id=$id'><input TYPE='submit' VALUE='Delete'></form></td>");
                        echo("</tr>");

                    }

                    mysqli_free_result($result); //Free up memory
                    mysqli_close($conn);

                echo("</table></center>");//Close off table now content has been added

            }
            else
            {
                echo("Unable to retrieve users from database!");
            }
        }

但是，当我删除其中一个帐户时，如果我关闭弹出窗口并通过按钮再次重新打开它，我删除的帐户仍然会显示在HTML表格中，但已从数据库中删除....有办法解决这个问题，或者每次弹出窗口都刷新，以便表格刷新？

MYSQL结果未更新

0 个答案: