客户方:
我已经使用AngularJS和NodeJS完成了文件上传工作但是在上传文件时我需要通过' name'和'电子邮件'到服务器。
服务器端:
将文件上传到文件夹后,我需要将文件路径,名称和电子邮件保存到数据库中。我怎么能这样做?
angular.module('fileUpload', ['ngFileUpload'])
.controller('MyCtrl',['Upload','$window',function(Upload,$window){
var vm = this;
vm.submit = function(){ //function to call on form submit
if (vm.upload_form.file.$valid && vm.file) { //check if from is valid
vm.upload(vm.file); //call upload function
}
}
vm.upload = function (file) {
console.log(vm.name);
console.log(vm.email);
Upload.upload({
url: 'http://localhost:3000/upload', //webAPI exposed to upload the file
data:{file:file} //pass file as data, should be user ng-model
}).then(function (resp) { //upload function returns a promise
if(resp.data.error_code === 0){ //validate success
$window.alert('Success ' + resp.config.data.file.name + 'uploaded. Response: ');
} else {
$window.alert('an error occured');
}
}, function (resp) { //catch error
console.log('Error status: ' + resp.status);
$window.alert('Error status: ' + resp.status);
}, function (evt) {
console.log(evt);
var progressPercentage = parseInt(100.0 * evt.loaded / evt.total);
console.log('progress: ' + progressPercentage + '% ' + evt.config.data.file.name);
vm.progress = 'progress: ' + progressPercentage + '% '; // capture upload progress
});
};
}]);

<script src="http://cdn.bootcss.com/danialfarid-angular-file-upload/12.2.13/ng-file-upload-shim.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular-file-upload/2.4.1/angular-file-upload.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<html>
<head>
<title>Home</title>
</head>
<body ng-app="fileUpload">
<h1>Angular Node File Upload</h1>
<form ng-controller="MyCtrl as up" name="up.upload_form">
name
<input type="text" ng-model="up.name"><br> <br>
email
<input type="text" ng-model="up.email"><br>
Image
<input
type="file"
ngf-select
ng-model="up.file"
name="file"
ngf-max-size="20MB"
/>
Image thumbnail: <img style="width:100px;" ng-show="!!up.file" ngf-thumbnail="up.file || '/thumb.jpg'"/>
<i ng-show="up.upload_form.file.$error.required">*required</i><br>
<i ng-show="up.upload_form.file.$error.maxSize">File too large
{{up.file.size / 1000000|number:1}}MB: max 20M</i>
<!-- Multiple files
<div class="button" ngf-select ng-model="up.files" ngf-multiple="true">Select</div>
Drop files: <div ngf-drop ng-model="up.files" class="drop-box">Drop</div> --><br>
<button type="submit" ng-click="up.submit()">submit</button>
<p>{{up.progress}}</p>
</form>
</body>
</html>
&#13;
后端代码:
var express = require('express');
var app = express();
var bodyParser = require('body-parser');
var multer = require('multer');
app.use(function(req, res, next) { //allow cross origin requests
res.setHeader("Access-Control-Allow-Methods", "POST, PUT, OPTIONS, DELETE, GET");
res.header("Access-Control-Allow-Origin", "http://localhost");
res.header("Access-Control-Allow-Headers", "Origin, X-Requested-With, Content-Type, Accept");
next();
});
/** Serving from the same express Server
No cors required */
app.use(express.static('../client'));
app.use(bodyParser.json());
var storage = multer.diskStorage({ //multers disk storage settings
destination: function (req, file, cb) {
cb(null, './uploads/');
},
filename: function (req, file, cb) {
var datetimestamp = Date.now();
cb(null, file.fieldname + '-' + datetimestamp + '.' + file.originalname.split('.')[file.originalname.split('.').length -1]);
}
});
var upload = multer({ //multer settings
storage: storage
}).single('file');
/** API path that will upload the files */
app.post('/upload', function(req, res) {
console.log(req.body);
upload(req,res,function(err){
if(err){
res.json({error_code:1,err_desc:err});
return;
}
res.json({error_code:0,err_desc:null});
});
});
app.listen('3000', function(){
console.log('running on 3000...');
});
我试过这个
Upload.upload({
url: 'http://localhost:3000/upload', //webAPI exposed to upload the file
data:{file:file, name:vm.name, email:vm.email} //pass file as data, should be user ng-model
})
后端
app.post('/upload', function(req, res) {
console.log(req.body);
console.log(req.file);
upload(req,res,function(err){
if(err){
res.json({error_code:1,err_desc:err});
return;
}
res.json({error_code:0,err_desc:null});
});
});
答案 0 :(得分:1)
您需要修改角度代码,以便在请求数据中发送额外信息
Upload.upload({
url: 'http://localhost:3000/upload', //webAPI exposed to upload the file
data:{file:file, name:vm.name, email:vm.email} //pass file as data, should be user ng-model
})
然后在您的后端代码中,您可以在请求正文中引用它
req.body.name
req.body.email
答案 1 :(得分:0)
您可以添加一个包含file
的文件属性,并更新data property to contain email and name
对象中的Upload.upload
。通过这种方式,您可以在服务器端轻松获取它们。
注意:我已更新了我的答案,我将所有值Angular view
包含在params
对象中。我还改变了angular-ng-upload CDN并没有在codepen上工作。您还应该先加载Angular.js
。
查看强>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<script src="https://angular-file-upload.appspot.com/js/ng-file-upload-shim.js"></script>
<script src="https://angular-file-upload.appspot.com/js/ng-file-upload.js"></script>
<html>
<head>
<title>Home</title>
</head>
<body ng-app="fileUpload">
<h1>Angular Node File Upload</h1>
<form ng-controller="MyCtrl as up" name="up.upload_form">
name
<input type="text" ng-model="up.params.name"><br> <br>
email
<input type="text" ng-model="up.params.email"><br>
Image
<input
type="file"
ngf-select
ng-model="up.params.file"
name="file"
ngf-max-size="20MB"
/>
Image thumbnail: <img style="width:100px;" ng-show="!!up.params.file" ngf-thumbnail="up.params.file || '/thumb.jpg'"/>
<i ng-show="up.upload_form.params.file.$error.required">*required</i><br>
<i ng-show="up.upload_form.params.file.$error.maxSize">File too large
{{up.params.file.size / 1000000|number:1}}MB: max 20M</i>
<!-- Multiple files
<div class="button" ngf-select ng-model="up.files" ngf-multiple="true">Select</div>
Drop files: <div ngf-drop ng-model="up.files" class="drop-box">Drop</div> --><br>
<button type="submit" ng-click="up.submit()">submit</button>
<p>{{up.progress}}</p>
<p>{{up.params}}{{up.params.file.size}}</p>
</form>
</body>
</html>
<强>角强>
var vm = this;
vm.submit = function(){
if (vm.upload_form.file.$valid && vm.params.file) {
console.log(vm.params)
vm.upload(vm.params); // Pass the `vm.params` object.
}
}
vm.upload = function (params) {
console.log(params.name); // params.name should be available
console.log(params.email); // params.email should be available
console.log(params.file); // params.file should be available
Upload.upload({
url: 'http://localhost:3000/upload',
file: params.file, // Image to upload
data: {
name: params.name,
email: params.email
}
})
}
<强>的Node.js /表达强>
app.post('/upload', function(req, res) {
console.log(JSON.parse(req.body.data)); // email and name here
console.log(req.files.file); // file object
upload(req,res,function(err){
if(err){
res.json({error_code:1,err_desc:err});
return;
}
res.json({error_code:0,err_desc:null});
});
});
答案 2 :(得分:0)
我不确定我的回答是否会对您有所帮助。但您可以在数据中添加姓名和电子邮件。
Upload.upload({
url: 'http://localhost:3000/upload', //webAPI exposed to upload the file
data:{file:file,name:"putHeretheName",email:"putHereTheMail"} //pass file as data, should be user ng-model
}
然后在服务器端,您可以创建一个功能或完成您的实际&#34; /上传&#34;使用查询保存在您的bdd中您想要的内容。您只需获取所创建路径的名称,然后在上传成功的情况下进行保存。