Question

如何在调用此函数时获取表单的发布数据

$(window).load(function()

使用以下内容获取值但不执行任何操作。

$('#id_state').val();

Answer 1

如果我没错，这就是你需要的：

<script>
    $(window).load(function(){
        var id_state=<?php if(isset($_POST["id_state"]){echo $_POST["id_state"];}else{ echo 0;}?>;
    });
</script>

Answer 2

尝试使用ajax

提交表单

下面的例子不是一个完美的答案。

<!DOCTYPE html>
<html>
    <head>
        <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
    </head>
    <body>
        <form id="formoid" action="studentFormInsert.php" title="" method="post">
            <div>
                <label class="title">First Name</label>
                <input type="text" id="name" name="name" >
            </div>
            <div>
                <label class="title">Name</label>
                <input type="text" id="name2" name="name2" >
           </div>
           <div>
               <input type="submit" id="submitButton"  name="submitButton" value="Submit">
           </div>
       </form>
       <script type='text/javascript'>
           /* attach a submit handler to the form */
           $("#formoid").submit(function(event) {

              /* stop form from submitting normally */
              event.preventDefault();

              /* get the action attribute from the <form action=""> element */
              var $form = $( this ),
              url = $form.attr( 'action' );

              /* Send the data using post with element id name and name2*/
              var posting = $.post( url, { name: $('#name').val(), name2: $('#name2').val() } );

              /* Alerts the results */
              posting.done(function( data ) {
                  alert('success');
              });
          });
      </script>
</body>

如何在jquery中获取window.load上的post数据

2 个答案: