Question

我试图通过递增一个变量（t）来运行一个小方程式，但只是每500次打印一次结果。我正在使用计数器函数和余数来指示何时我有一个整数值，然后打印。在此代码中，它不会打印任何内容。如果我将计数器设置为＆＃34; counter = counter + 5＆＃34;，它将运行并递增x 5，但每次都打印。你能看出什么问题吗？你可以看到我评论了一些我正在尝试的东西。我认为解决方案是这样的，但我无法弄清楚！

t = 0
counter = 0
#mass rocket = 4390
#mass fuel at launch =
mass= 13000
v = 0
a = 0
d = 0
deltat=.001

#gd = gdisplay(x=0, y=0, width=100, height=4000, title='v vs. t', xtitle='t', ytitle='v',foreground=color.black, background=color.white, xmax=70, xmin=0, ymax=4000, ymin=0)
while (t<=65):
    t = t + deltat
    mass = 13000 - (130*t)
    v = v + ((1880*(130*deltat))/(mass))
    a = ((1880/(mass))*((130*deltat)/(deltat)))
    d = d + ((v*deltat)+((.5)*a*(deltat*deltat)))
    #counter += .001
    counter = counter + t
    #counter%5==0
    if counter %5 == 0:
        print (counter)
        print (t)
        print (v)
        #print a
        print (d)

我试过这个并没有运行。没有错误，它只是没有做任何事情。

t = 0
counter = 0
#mass rocket = 4390
#mass fuel at launch =
mass= 13000
v = 0
a = 0
d = 0
deltat=.001

#gd = gdisplay(x=0, y=0, width=100, height=4000, title='v vs. t', xtitle='t', ytitle='v',foreground=color.black, background=color.white, xmax=70, xmin=0, ymax=4000, ymin=0)
while (t<=65):
    t = t + deltat
    mass = 13000 - (130*t)
    v = v + ((1880*(130*deltat))/(mass))
    a = ((1880/(mass))*((130*deltat)/(deltat)))
    d = d + ((v*deltat)+((.5)*a*(deltat*deltat)))
    #counter = counter + 5.0
    if t % 1.0 == 0:
        #print (counter)
        print (t)
        print (v)
        print (d)

Jeepers-对不起，我真是太愚蠢了。我厌倦了它，只运行一次：

t = 0
counter = 0
#mass rocket = 4390
#mass fuel at launch =
#mass= 13000
v = 0
a = 0
d = 0
deltat=.001

#gd = gdisplay(x=0, y=0, width=100, height=4000, title='v vs. t', xtitle='t', ytitle='v',foreground=color.black, background=color.white, xmax=70, xmin=0, ymax=4000, ymin=0)
while (t<=65):
    t = t + deltat
    mass = 13000 - (130*t)
    v = v + ((1880*(130*deltat))/(mass))
    a = ((1880/(mass))*((130*deltat)/(deltat)))
    d = d + ((v*deltat)+((.5)*a*(deltat*deltat)))
    #counter += 1
    if counter % 500 == 0:
        print (counter)
        print(t)
        print(v)
        print(d)
        counter += 1

如果我将计数器增加到if语句之上，它会将t增加.5s而不是.001，并递增计数x 500.我很困惑。

t = 0
counter = 0
#mass rocket = 4390
#mass fuel at launch =
#mass= 13000
v = 0
a = 0
d = 0
deltat=.001

#gd = gdisplay(x=0, y=0, width=100, height=4000, title='v vs. t', xtitle='t', ytitle='v',foreground=color.black, background=color.white, xmax=70, xmin=0, ymax=4000, ymin=0)
while (t<=65):
    t = t + deltat
    mass = 13000 - (130*t)
    v = v + ((1880*(130*deltat))/(mass))
    a = ((1880/(mass))*((130*deltat)/(deltat)))
    d = d + ((v*deltat)+((.5)*a*(deltat*deltat)))
    counter += 1
    if counter % 500 == 0:
        print (counter)
        print(t)
        print(v)
        print(d)

Answer 1

增量计数器如下：

counter += 1

并像这样打印

if counter % 500 == 0:
    print (counter)

每隔1分钟添加一个计数器语句来打印值

1 个答案: