Question

我有一个包含文本字符串的textarea，我将其值传递给名为updatestring的变量。我收到的文字区域中的文字被update(){和}括起来了。本文进入变量updatecode。

var updatestring = 'update(){\n//logic code here...\n\n\n}\n' ;
var updatecode = updatestring.match(/update\(\)\{([^}]+)\}/)[1];

我遇到的问题是，我希望update(){和}所包含的文字也包含字符}。在JavaScript中，有没有简单的方法可以在不使用库的情况下执行此操作？

Answer 1

Edit: torazaburo's answer is better, but I'll leave this here to show another way just for educational purposes. ;)

Try this: /[^{]*{((?:.|\r|\n)*)}/

Example: https://regex101.com/r/QOIyvz/4

[^{]* - skips all characters until { is found and stops just before it.

{ - matches the first brace.

((?:.|\r|\n)*) - ?: starts a non-capturing group (will not be returned), and * "greedily" matches all characters and carriage return and line feeds, and makes them all part of a captured group (between the other ( and )) that is returned.

} - Regex will stop the greedy search to match the last one found.

Example: updatestring.match(/[^{]*{((?:.|\r|\n)*)}/)[1]

Answer 2

贪婪匹配（这是*的默认行为）将跳过中间}个字符直到最后一个字符，因此不需要任何特殊内容：

＆＃13;

var updatestring = 'update(){\n//logic {embedded curly brackets}code here...\n\n\n}\n' ;    

var regexp = /{([^]*)}/;
//            ^                match starting curly
//             ^^^^^^          capture
//              ^^^            any character including newline
//                 ^           any number of times
//                   ^         match ending curly

var regexp = result = updatestring.match(regexp)[1];

console.log(updatestring, result);

＆＃13;

[^]将匹配包括换行符在内的所有内容。

顺便说一下，为什么要尝试使用regexp解析看起来像JavaScript的东西？

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