将List [String]转换为带有Scala引用的String

Question

是否有一种简单的方法可以将List [String]转换为包含"和,的String格式。例如

val fruits: List[String] = List("Apple", "Banana", "Grapes", "Pears")
==> "Apple", "Banana", "Grapes", "Pears"

我想这样做是因为我必须将结果附加到JSON字符串中。

{
 ....,
 "fruits": ["Apple", "Banana", "Grapes", "Pears"],
 ....
}

Answer 1

fruits.mkString("\"fruits\": [\"", "\",\"", "\"]")

但我会使用类似https://github.com/circe/circe的内容，而不是自己构建JSON