Question

指定将一个给定的字符串变成瑞典强盗语言，这意味着短语中的每个辅音都会加倍，并且中间放置一个“o”。例如，“这很有趣”将变成'tothohisos isos fofunon'。它还需要处于“翻译”功能中。让我知道我做错了什么。请尽量简单地解释，我不是很先进：）

old_string="this is fun"

vowels=("a", "A", "e", "E", "i", "I", "o", "O", "u", "U")

def translate(old_string):

l=len(old_string)

for let in old_string[0:l]:
    for vow in vowels:
        if let!=vow:
            print str(let)+'o'+str(let)

print translate(old_string)

我得到的输出是'tot 合计合计合计合计合计合计合计合计合计无

Answer 1

你的代码有很多循环。这是你的代码更加pythonic。

# define vowels as a single string, python allows char lookup in string
vowels = 'aAeEiIoOuU'

# do not expand vowels or spaces
do_not_expand = vowels + ' '    

def translate(old_string):
    # start with an empty string to build up
    new_string = ''

    # loop through each letter of the original string
    for letter in old_string:

        # check if the letter is in the 'do not expand' list
        if letter in do_not_expand:

            # add this letter to the new string
            new_string += letter

        else:
            # translate this constant and add to the new string
            new_string += letter + 'o' + letter

    # return the newly constructed string
    return new_string

print translate("this is fun")

Answer 2

试试这个：

def translate(old_string):
  consonants = set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")
  return ''.join(map(lambda x: x+"o"+x if x in consonants else x, old_string))

工作小提琴here。

编辑：以下是您的解决方案的更正版本：

old_string="this is fun"

vowels=("a", "A", "e", "E", "i", "I", "o", "O", "u", "U")

def translate(old_string):

  l=len(old_string)
  translated = ""
  for let in old_string[0:l]:
      if let not in vowels and let != " ":
        translated += let + "o" + let
      else:
        translated += let
  return translated

print translate(old_string)

工作小提琴here。

瑞典强盗翻译

2 个答案: