在TypeScript中，如何键入对象文字的特定键

Question

所以我有这个数据结构

export interface StoreData {
    msdb: {[tableName: string]: List<StoreModel>};
}

但我想只允许（并获取IntelliSence）我的tableName的特定字符串值。 所以我尝试了类似下面的内容，但它没有工作：

var tableNames:'table_campaigns' | 'table_resources'
export interface StoreData {
    msdb: {[tableName]: List<StoreModel>};
}

也尝试没有运气

interface IMyTables {
    'table_campaigns: string
    'table_resources: string;
}

type MyTables = keyof IMyTables;

export interface StoreData {
    participants: { [key: number]: any };
    threads: { [key: number]: any };
    messages: { [key: number]: any };
    msdb: {MyTables: List<StoreModel>};
}

也尝试了

type allMyTables = 'table_campaigns' | 'table_resources'

export interface StoreData {
    msdb: {[tableName: allMyTables]: List<StoreModel>};
}




Thanks for reading,

Sean

Answer 1

谢谢杰夫，做到了：

export interface StoreData {
    participants: { [key: number]: any };
    threads: { [key: number]: any };
    messages: { [key: number]: any };
    msdb: {
        'table_campaigns': List<StoreModel>;
        'table_resources': List<StoreModel>;
    };
}