$emparray=array();
while($row = mysqli_fetch_array($result,MYSQL_NUM))
{
foreach ($row as $key => $value)
{
if ($value == '')
{
$row[9] ='We follow-up you';
}
}
$emparray[] = array
('success' => true,
'message' => "audio saved Successfully!",
array('client_cname' => $row[2],
'future_followup' => $row[8],
'notes' => $row[9]));
}
**如上所示,这是我使用while循环从db获取记录的代码。 问题是我得到所有记录,但与不同的arrys。我希望它只有一个索引**
的数组 [
{
"success": true,
"message": "audio saved Successfully!",
"0": {
"client_cname": "Hhhs",
"future_followup": "4 Jan 2017 05:17 PM",
"notes": "hey"
}
},
{
"success": true,
"message": "audio saved Successfully!",
"0": {
"client_cname": "Hcjc",
"future_followup": "4 Jan 2017 06:17 PM",
"notes": "hey"
}
}
]
以上是我的O / P
我希望它以下面的格式请帮助我。
{
"status": "true",
"message": "Audio Saved successfully!"
[
{
"client_cname": "Atul",
“future_followup": “”,
“notes": “”,
},
{
"client_cname": "Atul",
“future_followup": “”,
“notes": “”,
}
]
}
如果我从$ emparray中删除 - > [],那么我将只获得如下代码的最后一行代码
{
"success": true,
"message": "audio saved Successfully!",
"0": {
"client_cname": "Hcjc",
"future_followup": "4 Jan 2017 06:17 PM",
"notes": "hey"
}
}
但我希望这种结果带有索引0,1,2等等。
请帮我一样。提前谢谢。
答案 0 :(得分:0)
以下是您需要做的事情:
if(mysqli_num_rows($result)>0) { //if there are any results
//initialise the array with the first two values
$emparray = array(
'success' => true,
'message' => "audio saved Successfully!");
}
while($row = mysqli_fetch_array($result,MYSQL_NUM))
{
foreach ($row as $key => $value)
{
if ($value == '')
{
$row[9] ='We follow-up you';
}
}
//append each data item as an array
$emparray[] = array('client_cname' => $row[2],
'future_followup' => $row[8],
'notes' => $row[9]));
}
这也将从0开始以数字方式自动索引所有其他数组。
答案 1 :(得分:0)
May be this is more better way to deal with.
$dataSet = array();
while ($row = mysqli_fetch_array($result, MYSQL_NUM)) {
foreach ($row as $key => $value) {
if ($value == '') {
$row[9] = 'We follow-up you';
}
}
$dataSet[] = array('client_cname' => $row[2],
'future_followup' => $row[8],
'notes' => $row[9]);
}
$emparray = array
('success' => true,
'message' => "audio saved Successfully!",
'data' => $dataSet);
echo json_encode($emparray);