获取ListView中LongClicked项的位置

Question

我有ListView显示自定义视图（每个项目3 TextViews）;我刚刚实现了这样的上下文菜单：

// in onCreateView
ListView list = (ListView) view.findViewById(R.id.list);

registerForContextMenu(list);

和

@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);

    if (v.getId() == R.id.list) {
        MenuInflater inflater = getActivity().getMenuInflater();
        inflater.inflate(R.menu.todo_context_menu, menu);
    }
}

@Override
public boolean onContextItemSelected(MenuItem item) {
    switch (item.getItemId()) {
        case R.id.edit:
            // your first action code
            return true;
        case R.id.delete:
            // your second action code
            return true;
        default:
            return super.onContextItemSelected(item);
    }
}

我希望知道哪个项目已被长时间点击（它在ListView中的位置是理想的），以便编辑或删除正确的项目。

怎么可能实现？

Answer 1

@Override
public boolean onContextItemSelected(MenuItem item) {

   AdapterView.AdapterContextMenuInfo info = (AdapterView.AdapterContextMenuInfo) item.getMenuInfo();
   int index = info.position;

  switch (item.getItemId()) {
    case R.id.edit:
        // your first action code
        return true;
    case R.id.delete:
        // your second action code
        return true;
    default:
        return super.onContextItemSelected(item);
  }
}