Apache Oltu + Twitter集成示例不起作用

时间:2017-01-09 12:31:35

标签: spring-mvc twitter twitter-oauth oltu

我正在开发 Spring MVC + Apache Oltu + Twitter 示例。在此示例中,我通过在此处注册/创建应用程序,从链接https://apps.twitter.com/app/new创建了client Id and Secrete。现在在ClientId和Secrete的帮助下,我想调用Twitter的REST API。我也按照该链接获取了scope https://developers.artsy.net/docs/authentication

我在我的应用程序中使用了以下参数:

AUTHORIZATION_URL = "https://api.twitter.com/oauth/authorize";
CLIENT_ID = "RSvE3qVXXXXXXXXXXXXXXXX";
CLIENT_SECRET = "nKEWRoOcXXXXXXXXXXXXXXXXXXXXXXXXXXXX";
REDIRECT_URL = "http://localhost:8080/apache-oltu/twitter/redirect";
ACCESS_TOKEN_URL = "https://api.twitter.com/oauth/access_token";

clientIdsecrete出于安全目的,我未在此处正确显示。现在,当我打电话给我的控制器时,我发现Twitter有以下错误。

enter image description here

我的控制器实际上是重定向到:

https://api.twitter.com/oauth/authorize?scope=offline_access&response_type=code&redirect_uri=
http%3A%2F%2Flocalhost%3A8080%2Fapache-oltu%2Ftwitter%2Fredirect&client_id=RSvE3qV6Hxfdgv39RJIjDvhhc

请指导/帮助我这里出了什么问题。有什么帮助吗?

scope=offline_access是否正确?我已经从我的

分享了一些代码
controller:
@Controller
@RequestMapping("/twitter")
public class TwitterController {
    private static final Logger LOGGER = LoggerFactory.getLogger(TwitterController.class);

    private static final String AUTHORIZATION_URL = "https://api.twitter.com/oauth/authorize";
    private static final String CLIENT_ID = "RSvE3qVXXXXXXXXXXXXXXXXXXXXXX";
    private static final String CLIENT_SECRET = "nKEWRoXXXXXXXXXXXXXXXXXXXXXXXXXX";
    private static final String REDIRECT_URL = "http://localhost:8080/apache-oltu/twitter/redirect";
    private static final String ACCESS_TOKEN_URL = "https://api.twitter.com/oauth/access_token";

    @RequestMapping(value = "/auth", method = RequestMethod.GET)
    public String authenticate() throws OAuthSystemException {
        OAuthClientRequest request = OAuthClientRequest
                .authorizationLocation(AUTHORIZATION_URL)
                .setClientId(CLIENT_ID)
                .setRedirectURI(REDIRECT_URL)
                .setResponseType("code")
                .setScope("offline_access")
                .buildQueryMessage();

        System.out.println("REDIRECT TO: "+request.getLocationUri());
        return "redirect:" + request.getLocationUri();
    }

    @RequestMapping(value = "/redirect", method = RequestMethod.GET)
    public HttpEntity<String> redirect(@RequestParam(value = "code", required = false) String code) throws OAuthSystemException, OAuthProblemException {
        String value = "UNKNOWN";

        if (code != null && code.length() > 0) {
            System.out.println("Received CODE: "+code);
            getAccessToken(code);
            value = code;
        }

        return new ResponseEntity<String>(value,HttpStatus.OK);
    }
..........................
.........................
}

任何帮助?

1 个答案:

答案 0 :(得分:0)

请参阅此文档。 https://dev.twitter.com/web/sign-in/implementing

我认为您需要在调用授权网址(https://api.twitter.com/oauth/request_token)之前调用请求令牌网址(https://api.twitter.com/oauth/authorize)以获取oauth_token。

这是额外的步骤和其他OAuth提供商......