Question

如何在LIstview和ModelFormMixin的以下实现中获取当前登录的用户：

class ListMessages(ListView, ModelFormMixin):
model = Message
template_name = 'accounts/list_messages.html'
context_object_name = 'messages'
form_class = MessageHiddenUserForm
#success_url = reverse_lazy('accounts:list_messages', kwargs={'uname': })

def post(self, request, *args, **kwargs):
    self.object = None
    self.form = self.get_form(self.form_class)

    if self.form.is_valid():
        self.form.user_to = self.kwargs['uname']
        self.form.user_from = request.user #this doesn't work
        self.object = self.form.save()

    return self.get(request, *args, **kwargs)

Answer 1

问题不在于您从哪里获取用户，而是您将其分配到的位置。在表单上设置任意属性根本不做任何事情;您需要将其分配给form.save的结果。

obj = self.form.save(commit=False)
obj.user_to = self.kwargs['uname']
obj.user_from = request.user
obj.save()

注意，您不能直接调用self.get();成功发布后，您必须始终重定向。

return redirect('accounts:list_messages', kwargs={...})

Answer 2

方法＆＃34; post＆＃34;使用request.user.username获取当前登录用户。

如何在ModelFormMixin post（）方法中获取当前用户？

2 个答案: