如何在foreach中返回多个值

Question

这是我的代码：

function get_roles(){
$role = array("1"=>"user management", "2"=>"create", "3"=>"update","4"=>"publish", "5"=>"delete", "6"=>"image upload", "7"=>"advertisement", "8"=>"department", "9"=>"category", "10"=>"sub category", "11"=>"grievance", "12"=>"feedback", "13"=>"help");
foreach($role as $x => $x_value) {
$result=  $x_value;   
}
return $result;
}
echo get_roles();

我想在php中将所有值作为json返回。但它只返回最后一个值。怎么做？是否可以返回所有值？

Answer 1

使用json_encode返回json字符串，如下所示：

return json_encode($role);

如果您希望索引从0开始，请使用return json_encode(array_values($role));

Answer 2

您需要为数组创建数组添加角色元素。

function get_roles(){
 $roles = array();
 $role = array("1"=>"user management", "2"=>"create", "3"=>"update","4"=>"publish", "5"=>"delete", "6"=>"image upload", "7"=>"advertisement", "8"=>"department", "9"=>"category", "10"=>"sub category", "11"=>"grievance", "12"=>"feedback", "13"=>"help");
 foreach($role as $x => $x_value) {
  $roles[] =  $x_value;   
 }
 return json_encode($roles);
}
echo get_roles();

Answer 3

请使用json_encode（）

function get_roles(){
$role = array("1"=>"user management", "2"=>"create", "3"=>"update","4"=>"publish", "5"=>"delete", "6"=>"image upload", "7"=>"advertisement", "8"=>"department", "9"=>"category", "10"=>"sub category", "11"=>"grievance", "12"=>"feedback", "13"=>"help");

return json_encode($role);
}
$getresult =  get_roles();
echo $getresult;

Answer 4

<?php

function get_roles(){
$role = array("1"=>"user management", "2"=>"create", "3"=>"update","4"=>"publish", "5"=>"delete", "6"=>"image upload", "7"=>"advertisement", "8"=>"department", "9"=>"category", "10"=>"sub category", "11"=>"grievance", "12"=>"feedback", "13"=>"help");
foreach($role as $x => $x_value) {
return json_encode($role);
}

}
print_r(get_roles());