我想从magento表中获取所有客户详细信息的行。
有人可以给我查询吗?
表格是:
答案 0 :(得分:25)
可以从Magento MySQL DB中提取一些数据,但在执行下面的查询之前,请注意以下事项:
1)Magento可以配置,因此您不能从MySQL获取数据,但必须使用Magento Customer模块(模型,资源模型)和Magento配置数据来检索客户数据。任何直接查询都不能保证与不同的Magento版本兼容,甚至不能与相同版本的安装兼容。
2)Magento EAV结构不允许您在一个查询中以漂亮的形式获取所有客户数据,因为表名称是动态匹配的。
3)您无法仅通过一个查询甚至多个查询提取所有客户数据。因为许多信息对象是在模型中创建的,只有模型具有在一个客户对象中收集所有数据的逻辑。我谈的是运费/账单地址,商店信用,奖励积分(EE版本)等等。
然而,只是为了获取所有客户的varchar属性,您可以使用以下代码(由于上面1中提到,不能保证工作):
SELECT ce.*, ea.attribute_code, cev.value
FROM customer_entity AS ce
LEFT JOIN eav_attribute AS ea ON ce.entity_type_id = ea.entity_type_id AND ea.backend_type = 'varchar'
LEFT JOIN customer_entity_varchar AS cev ON ce.entity_id = cev.entity_id AND ea.attribute_id = cev.attribute_id
此外,还可以使用此类查询来提取客户的所有属性
SELECT ce.*, ea.attribute_code,
CASE ea.backend_type
WHEN 'varchar' THEN ce_varchar.value
WHEN 'int' THEN ce_int.value
WHEN 'text' THEN ce_text.value
WHEN 'decimal' THEN ce_decimal.value
WHEN 'datetime' THEN ce_datetime.value
ELSE NULL
END AS value
FROM customer_entity AS ce
LEFT JOIN eav_attribute AS ea ON ce.entity_type_id = ea.entity_type_id
LEFT JOIN customer_entity_varchar AS ce_varchar ON ce.entity_id = ce_varchar.entity_id AND ea.attribute_id = ce_varchar.attribute_id AND ea.backend_type = 'varchar'
LEFT JOIN customer_entity_int AS ce_int ON ce.entity_id = ce_int.entity_id AND ea.attribute_id = ce_int.attribute_id AND ea.backend_type = 'int'
LEFT JOIN customer_entity_text AS ce_text ON ce.entity_id = ce_text.entity_id AND ea.attribute_id = ce_text.attribute_id AND ea.backend_type = 'text'
LEFT JOIN customer_entity_decimal AS ce_decimal ON ce.entity_id = ce_decimal.entity_id AND ea.attribute_id = ce_decimal.attribute_id AND ea.backend_type = 'decimal'
LEFT JOIN customer_entity_datetime AS ce_datetime ON ce.entity_id = ce_datetime.entity_id AND ea.attribute_id = ce_datetime.attribute_id AND ea.backend_type = 'datetime'
答案 1 :(得分:8)
为了补充@Stefano的回复,我提出了一个大问题,只是为了提取一些其他重要的细节,比如地址和电话。其中一些细节只对我的数据库有意义,但可以帮助某人:
SELECT c.entity_id,c.email,
(
SELECT fn.value
FROM customer_entity_varchar fn
WHERE c.entity_id = fn.entity_id AND
fn.attribute_id = 12) AS password_hash,
(
SELECT fn.value
FROM customer_entity_varchar fn
WHERE c.entity_id = fn.entity_id AND
fn.attribute_id = 5) AS name,
(
SELECT fn.value
FROM customer_entity_varchar fn
WHERE c.entity_id = fn.entity_id AND
fn.attribute_id = 7) AS lastname,
(
SELECT fn.value
FROM customer_entity_varchar fn
WHERE c.entity_id = fn.entity_id AND
fn.attribute_id = 150) AS cpfcnpj,
(
SELECT fn.value
FROM customer_address_entity_varchar fn
WHERE ca.entity_id = fn.entity_id AND
fn.attribute_id = 149) AS cpfcnpj2,
(
SELECT fn.value
FROM customer_address_entity_varchar fn
WHERE ca.entity_id = fn.entity_id AND
fn.attribute_id = 145) AS rg,
(
SELECT fn.value
FROM customer_address_entity_varchar fn
WHERE ca.entity_id = fn.entity_id AND
fn.attribute_id = 151) AS phone1,
(
SELECT fn.value
FROM customer_address_entity_varchar fn
WHERE ca.entity_id = fn.entity_id AND
fn.attribute_id = 31) AS phone2,
(
SELECT fn.value
FROM customer_address_entity_varchar fn
WHERE ca.entity_id = fn.entity_id AND
fn.attribute_id = 27) AS country,
(
SELECT fn.value
FROM customer_address_entity_varchar fn
WHERE ca.entity_id = fn.entity_id AND
fn.attribute_id = 28) AS state,
(
SELECT fn.value
FROM customer_address_entity_varchar fn
WHERE ca.entity_id = fn.entity_id AND
fn.attribute_id = 26) AS city,
cat.value AS address,
(
SELECT fn.value
FROM customer_address_entity_varchar fn
WHERE ca.entity_id = fn.entity_id AND
fn.attribute_id = 30) AS cep
FROM customer_entity AS c
LEFT JOIN customer_address_entity AS ca ON c.entity_id = ca.parent_id
LEFT JOIN customer_address_entity_text AS cat ON cat.entity_id = ca.entity_id
GROUP BY entity_id
答案 2 :(得分:7)
这是一个从magento表中提取客户详细信息的小问题:
select c.*,
(select fn.value from customer_entity_varchar fn where c.entity_id = fn.entity_id and
fn.attribute_id = 5) as Name,
(select fn.value from customer_entity_varchar fn where c.entity_id = fn.entity_id and
fn.attribute_id = 7) as Lastname
from customer_entity c
答案 3 :(得分:3)
我读到了上面的内容,我感觉好多了,因为有些人试图找出问题,就像我的一样。 好吧,正如您所知,您无法在magento后台找到有关您客户的全部信息。 我想要一张非常大的桌子,我可以看到我的所有客户(那些有帐户=注册的人)(以及那些刚刚注册到新闻通讯newsletter_subscribers的人)
由于我真的不知道magento是如何提供这些信息的,所以我编写了som SQL代码来提取数据。
如上所述,您无法在一个查询中获得有关客户端的所有信息。实际上,您将需要与客户端属性一样多的查询。 如果实体客户端有45个属性(name,lastname,middlename,email .....) 然后你将需要45个查询来提取它们...... 我的问题是如何???
答案是VIEWS !! 实际上,我编写了Views来提取每个属性信息。这意味着我写了45个视图,每个视图选择一个属性
我不知道它是如何在您的数据库中完成的,但是,您可能知道每个实体都有一个entity_type_id。 就我而言,我对customer_entity和customer_address_entity感兴趣。 customer_entity具有entity_type_id = 1 customer_address_entity具有entity_type_id = 2
每个实体都有属性。因此,如果您想查看客户实体可用的属性,请运行查询:
Select attribute_code, attribute_id, backend_type from eav_attribute where entity_type_id =1
通过将1替换为2,地址实体也是如此。
列attributes_id非常重要,因为这将使您能够通过id表来查找属性: entity_customer_vachar,entity_customer_int,entity_customer_text,entity_customer_datetime 你可能会在这张表中找到firstname attribute_id = 5,正如约瑟夫·马斯蒂在他的查询中所写的......
在上表中按类型分派信息。 当您运行上面的查询时,您将看到每个属性都有一个后端类型。这意味着您要查找的信息是其类型后缀的表之一。 例如,如果您要查找名称为varchar的名字,那么您将在customer_entity_varchar中找到它,依此类推。
如果你还在读书,那可能意味着你明白我在说什么。 另外,你需要看看EAV模型 和magento 1.3.2.4数据库架构在 http://inchoo.net/wp-content/uploads/2010/09/MAGENTO_v1.3.2.4-Database_Diagram.pdf
我无法发布整个解决方案,因为它尚未准备就绪,如果可以提供帮助,我会提供一个zip文件。
同时,如果有人知道如何在不编辑magento Core的情况下使用magento对象来获取数据,那就太棒了! 感谢
答案 4 :(得分:2)
您是在寻找这个或一些Magento代码的实际SQL吗?实际的SQL会变得混乱,并且可能永远不会像你想要的那样。
由于MySQL中没有“pivot”,你基本上可以忽略实际查询中的eav_attribute
。您将查看它以查找所需的属性ID。以下是如何选择此数据的简单示例:
select c.*, fn.value firstname
from customer_entity c
join customer_entity_varchar fn
on c.entity_id = fn.entity_id and fn.attribute_id = 5
;
继续为每个属性添加这些join子句,您将获得查询。基本上,EAV没有针对这种访问进行优化。
如果您更详细地介绍一下您要做的事情(或者Magento中的PHP代码是否适用于您的目的),我们可以为您提供进一步的帮助。
希望有所帮助!
谢谢, 乔
答案 5 :(得分:2)
我特意试图从我的Magento商店出口客户手机号码。
首先,您可以使用数据配置文件执行此操作,因为它扩展到客户数据集。
在我的情况下,数据配置文件功能由于某种原因无法工作,因为我没有时间解决为什么我直接使用MySQL来获取我的数据。
以下MySQL查询将使您能够使用英国移动电话号码提取客户。注意:您可能需要确定所需数据的attribute_id,并相应地在查询中更新。
attribute_id value
26 Country
19 First_Name
21 Surname
31 Telephone
QUERY: -
SELECT
`firstname`.`value` as `First_Name`,
`surname`.`value` as `Surname`,
`telephone`.`value` as `Telephone`,
`customer_entity`.`created_at`,
`customer_entity`.`updated_at`
FROM
`customer_address_entity_varchar` as `country`
INNER JOIN
`customer_address_entity_varchar` as `firstname` USING (`entity_id`)
INNER JOIN
`customer_address_entity_varchar` as `surname` USING (`entity_id`)
INNER JOIN
`customer_address_entity_varchar` as `telephone` USING (`entity_id`)
INNER JOIN
`customer_entity` USING (`entity_id`)
WHERE
`country`.`attribute_id` = 26 &&
`country`.`value`="GB" &&
`firstname`.`attribute_id` = 19 &&
`surname`.`attribute_id` = 21 &&
`telephone`.`attribute_id` = 31 &&
`telephone`.`value` LIKE "07%"
GROUP BY `telephone`.`value`
limit 0,10;
请注意限制和where语句将结果限制为特定数据,该组会停止重复的数字,因为我想要的实际数据是电话号码。您可以添加INTO OUTFILE以将结果集导出为CSV。
希望这有助于某人...
答案 6 :(得分:1)
SELECT customer_address_entity_varchar.value, customer_entity.entity_id
FROM customer_address_entity_varchar
LEFT JOIN customer_address_entity
ON customer_address_entity_varchar.entity_id = customer_address_entity.entity_id
LEFT JOIN customer_entity
ON customer_address_entity.parent_id = customer_entity.entity_id
WHERE attribute_id =31
答案 7 :(得分:0)
我修改了Andrey Tserkus的精彩答案。并添加了一个新的WHERE子句。现在您只需要更换产品SKU,您将获得购买产品的所有客户记录集。在Magento 1.5.1中可以正常使用
/* Just replace the value for i.sku in line 32, with the corresponding sku of the product you want to get the buyers from*/ SELECT `e`.*, `at_prefix`.`value` AS `prefix`, `at_firstname`.`value` AS `firstname`, `at_middlename`.`value` AS `middlename`, `at_lastname`.`value` AS `lastname`, `at_suffix`.`value` AS `suffix`, CONCAT(IF(at_prefix.value IS NOT NULL AND at_prefix.value != '', CONCAT(LTRIM(RTRIM(at_prefix.value)), ' '), ''), LTRIM(RTRIM(at_firstname.value)), ' ', IF(at_middlename.value IS NOT NULL AND at_middlename.value != '', CONCAT(LTRIM(RTRIM(at_middlename.value)), ' '), ''), LTRIM(RTRIM(at_lastname.value)), IF(at_suffix.value IS NOT NULL AND at_suffix.value != '', CONCAT(' ', LTRIM(RTRIM(at_suffix.value))), '') ) AS `name` FROM `customer_entity` AS `e` LEFT JOIN `customer_entity_varchar` AS `at_prefix` ON (`at_prefix`.`entity_id` = `e`.`entity_id`) AND (`at_prefix`.`attribute_id` = '4') LEFT JOIN `customer_entity_varchar` AS `at_firstname` ON (`at_firstname`.`entity_id` = `e`.`entity_id`) AND (`at_firstname`.`attribute_id` = '5') LEFT JOIN `customer_entity_varchar` AS `at_middlename` ON (`at_middlename`.`entity_id` = `e`.`entity_id`) AND (`at_middlename`.`attribute_id` = '6') LEFT JOIN `customer_entity_varchar` AS `at_lastname` ON (`at_lastname`.`entity_id` = `e`.`entity_id`) AND (`at_lastname`.`attribute_id` = '7') LEFT JOIN `customer_entity_varchar` AS `at_suffix` ON (`at_suffix`.`entity_id` = `e`.`entity_id`) AND (`at_suffix`.`attribute_id` = '8') WHERE (`e`.`entity_type_id` = '1') AND `e`.`entity_id` IN ( SELECT DISTINCT o.customer_id FROM sales_flat_order_item i INNER JOIN sales_flat_order o ON o.entity_id = i.order_id WHERE o.customer_id IS NOT NULL AND i.sku = '10-10-10101-4' ) LIMIT 1000
答案 8 :(得分:0)
我相信这可能是一个更简单的查询,没有子查询:
SELECT c.email, cv.value as fname, cv2.value as lname
FROM customer_entity c, customer_entity_varchar cv, customer_entity_varchar cv2
WHERE c.entity_id = $user_id
AND c.entity_id = cv.entity_id
AND cv.attribute_id = 5
AND c.entity_id = cv2.entity_id
AND cv2.attribute_id = 7
答案 9 :(得分:0)
以下是您可以在Magento中获取客户详细信息的代码
if (Mage::getSingleton('customer/session')->isLoggedIn()) {
$customer = Mage::getSingleton('customer/session')->getCustomer();
$customerData = Mage::getModel('customer/customer')->load($customer->getId())->getData();
Mage::log($customerData);}
其输出将如下所示: -
Array
(
[entity_id] => 1
[entity_type_id] => 1
[attribute_set_id] => 0
[website_id] => 1
[email] => test@example.com
[group_id] => 1
[increment_id] => 000000001
[store_id] => 1
[created_at] => 2007-08-30 23:23:13
[updated_at] => 2008-08-08 12:28:24
[is_active] => 1
[firstname] => Test
[lastname] => User
[password_hash] => 204948a40200e4238db2277d5:eg
[prefix] =>
[middlename] =>
[suffix] =>
[taxvat] =>
[default_billing] => 274
[default_shipping] => 274
)
答案 10 :(得分:0)
另一个用于获取属性值的示例sql代码。我只使用了int和varchar属性,你也可以添加其他属性。
select c.entity_id, c.email,
a.attribute_id, a.attribute_code, a.frontend_label, a.backend_type, a.frontend_input,
case a.backend_type
when 'int' then coalesce(o.value, cei.value)
when 'varchar' then cev.value
end as value
from customer_entity c
left join eav_attribute a on a.entity_type_id = c.entity_type_id
left join customer_entity_int cei on a.backend_type = 'int' and cei.attribute_id = a.attribute_id and cei.entity_id = c.entity_id and cei.entity_type_id = c.entity_type_id
left join customer_entity_varchar cev on a.backend_type = 'varchar' and cev.attribute_id = a.attribute_id and cev.entity_id = c.entity_id and cev.entity_type_id = c.entity_type_id
left join eav_attribute_option_value o on a.backend_type = 'int' and a.frontend_input = 'select' /* and o.store_id = c.store_id */ and o.option_id = cei.value
-- where c.entity_id = 17651
having value is not null
order by c.entity_id, a.attribute_code;