Question

我正在尝试从Firebase数据库中的DownloadURl中获取Firebase存储中的图片..

Firebase结构

用户

|的 _9304809841

    |__IMAGE :"https://firebasestorage.googleapis.com/v0/b/zumi- 
              60a8f.appspot.com/o/Profile_Image%2Fcropped-122662379.jpg?
             alt=media&token=c8f3e9ee-637d-4bdd-9a76-a186ecd07e37"

我使用下面的代码从URL获取图像..

final DefaultHttpClient client = new DefaultHttpClient();
            final HttpGet getRequest = new HttpGet(URL);  //FETCHING THE URL FROM FIREBASE DATABASE..
            try {

                HttpResponse response = client.execute(getRequest);

                //check 200 OK for success
                final int statusCode = response.getStatusLine().getStatusCode();

                if (statusCode != HttpStatus.SC_OK) {
                    //Toast.makeText(MainActivity.this, "Error in HttpSTATUS", Toast.LENGTH_SHORT).show();
                    //return;

                }

                final HttpEntity entity = response.getEntity();
                if (entity != null) {
                    InputStream inputStream = null;
                    try {
                        // getting contents from the stream
                        inputStream = entity.getContent();
                        //inputStream = (InputStream) new URL(params[0].toString()).getContent();

                        byte[] image = new byte[inputStream.available()];
                        inputStream.read(image);
                        values.put("image", image); //inserting the Values into ContentVAlues



                    } finally {
                        if (inputStream != null) {
                            inputStream.close();
                        }
                        entity.consumeContent();
                    }
                    if (values != null) {
                        Cdb.insert("current_Luser", null, values); // INSERTING INTO SQLite DB
                    }
                }
                else
                {
                    //Toast.makeText(MainActivity.this, "Entity is Null", Toast.LENGTH_SHORT).show();
                }
            } catch (Exception e) {
                // You Could provide a more explicit error message for IOException
                getRequest.abort();
                Log.d("",e.toString());
               // Toast.makeText(MainActivity.this, "Error "+e.toString(), Toast.LENGTH_SHORT).show();
            }

            return null;
        }

    }

我正在尝试使用

检索图像

Cursor c=Cdb.rawQuery("select email_phone,status,Dname,image from current_Luser",null);

        Toast.makeText(this, "No of record : "+c.getCount(), Toast.LENGTH_SHORT).show();
        if(c.moveToNext()) {

            if (c.getCount() > 0) {
                email.setText(c.getString(0).replace("@zumi.com", "").toString());
                name.setText(c.getString(2));
                status.setText(c.getString(1));
                byte[] img = c.getBlob(3);
                Bitmap bmp = BitmapFactory.decodeByteArray(img, 0, img.length);
                showpotos.setImageBitmap(bmp);

             }

将数据作为[B @ d0ca6a3值插入到SQLite DB中...但它不会显示在图像视图中....

请帮助..

Answer 1

在此声明中使用available(）可能会导致问题：

byte[] image = new byte[inputStream.available()]

documentation for available()说：

请注意，虽然InputStream的某些实现将返回流中的总字节数，很多都不会。永远不会正确使用此方法的返回值来分配缓冲区旨在保存此流中的所有数据

从firebase获取图像并插入SQLite并显示到图像视图中...

1 个答案: