这是我的示例代码请帮帮我们
<?php
$con =mysql_connect("localhost", "" , "");
$sdb= mysql_select_db("image",$con);
$sql = "SELECT * FROM `tbl_image` WHERE id=21";
$mq = mysql_query($sql) or die ("not working query");
$row = mysql_fetch_array($mq) or die("line 44 not working");
$s = $row['img_url'];
echo '<img src="'.$s.'">';
?>
答案 0 :(得分:0)
循环行。
$mq = mysql_query($sql) or die ("not working query");
while ($row = mysql_fetch_array($mq)) {
echo '<img src="' . $row['img_url'] . '" >';
}
答案 1 :(得分:0)
应该将最后两行更改为此
while ($row = mysql_fetch_assoc($result)) {
$s = $row['img_url'];
echo '<img src="'.$s.'">';
}
答案 2 :(得分:0)
<?php
$con = mysql_connect("localhost", "" , "");
$sdb = mysql_select_db("image",$con);
$sql = "SELECT * FROM `tbl_image` WHERE id=21";
//echo "SELECT * FROM `tbl_image` WHERE id=21"; //and run the query in database if it is working fine then you can use while loop.
$mq = mysql_query($sql) or die ("not working query"); // if this line is not working try eho the above query like i have mentioned in comments.
while ( $row = mysql_fetch_array($mq)) {
echo '<img src="' . $row['img_url'] . '" >';
}
?>
答案 3 :(得分:-1)
您可以尝试以下代码。
while($row=mysql_fetch_object($qry))
{
$result[] = $row['img_url'];
echo '<img src="' . $row['img_url'] . '" >';
}
print_r($result)