Question

请原谅下面的代码块，我为了清楚起见而提出这些代码。谢谢！

我有一个类型为[TestSuiteDetail]的表视图控件[suiteCasesSelected]，它具有以下功能：

我从本教程获得的过滤功能：JavaFX 8 TableView Sorting and Filtering

//Triggered every time I type something on the filter box
private void filterTestSuiteSelectedList() {
    // Wrap the ObservableList in a FilteredList (display all data).
    FilteredList<TestSuiteDetail> filteredData = new FilteredList<>(mainApp.getTestSuiteSelectedData(), p -> true);

    // Set the filter Predicate whenever the filter changes.
    suiteSelectedFilter.textProperty().addListener((observable, oldValue, newValue) -> {
        filteredData.setPredicate(tc -> {
            // Display all if filter is empty
            if (newValue == null || newValue.isEmpty()) {
                return true;
            }
            // Compare test case name or module name
            String lowerCaseFilter = newValue.toLowerCase();
            if (tc.getTestCaseName().toLowerCase().contains(lowerCaseFilter)) {
                return true;
            } else if (tc.getModuleName().toLowerCase().contains(lowerCaseFilter)) {
                return true;
            }
            return false;
        });
    });

    // Wrap the FilteredList in a SortedList.
    SortedList<TestSuiteDetail> sortedData = new SortedList<>(filteredData);

    // Bind the SortedList comparator to the TableView comparator.
    sortedData.comparatorProperty().bind(suiteCasesSelected.comparatorProperty());

    // Add sorted and filtered data to the table.
    suiteCasesSelected.setItems(sortedData);
}

通过按下按钮从列表中删除项目：

@FXML
private void handleRemoveFromSelectedClicked() {
    ObservableList selectedItems = suiteCasesSelected.getSelectionModel().getSelectedItems();
    if (selectedItems != null) {
        suiteCasesSelected.getItems().removeAll(selectedItems);
        mainApp.saveSuiteDetailsSelectedXMLData(testSuite);
        TestNGXmlConverter.updateTestSuiteXMLFile(testSuite.getTestSuiteName());
    }
}

我的问题：
每次我从表格中选择项目，然后点击删除＆＃39;＆lt;＆lt;＆lt;＆＃39;按钮，我从

开始有多个例外

 Exception in thread "JavaFX Application Thread" java.lang.RuntimeException: java.lang.reflect.InvocationTargetException

最后以

结束

 Caused by: java.lang.UnsupportedOperationException
at java.util.AbstractList.remove(Unknown Source)
at java.util.AbstractList$Itr.remove(Unknown Source)
at java.util.AbstractCollection.removeAll(Unknown Source)
at cl.oe.beatrix.view.ControllerWindowMain.handleRemoveFromSelectedClicked(ControllerWindowMain.java:2043)
... 70 more

第2043行指向上面显示的suiteCasesSelected.getItems().removeAll(selectedItems);。

其他信息：

我在控制器类的filterTestSuiteSelectedList()方法上调用了整个过滤方法initialize()。

只有在我放入过滤功能时才会发生异常。如果我发表评论，它的工作正常。

感谢您的帮助！如果需要进一步的信息，请告诉我们！

Table snapshot

Answer 1

管理解决这个问题。

用户遇到类似问题并将其发布在教程See the comments all the way below the blog post中。

原材料：

// The index of the sorted and filtered list.
int visibleIndex = personTable.getSelectionModel().getSelectedIndex();

// Source index of master data.
int sourceIndex = sortedData.getSourceIndexFor(masterData, visibleIndex);

// Remove.
masterData.remove(sourceIndex);

根据我的情况修改（多选表）：

@FXML
private void handleRemoveFromSelectedClicked() {
    // Get all the selected items
    ObservableList<Integer> selectedItems = suiteCasesSelected.getSelectionModel().getSelectedIndices();
    if (selectedItems != null) {
        // Iterate through each item
        for (Integer selectedItem : selectedItems) {
            int sourceIndex = filteredSelectedData.getSourceIndexFor(mainApp.getTestSuiteSelectedData(),
                    selectedItem.intValue());
            //remove        
            mainApp.getTestSuiteSelectedData().remove(sourceIndex);
        }

        mainApp.saveSuiteDetailsSelectedXMLData(testSuite);
        TestNGXmlConverter.updateTestSuiteXMLFile(testSuite.getTestSuiteName());
    }
}

谢谢！

Answer 2

由于external jar和FilteredList只是列表的视图，因此它们不可修改;只能通过修改支持列表来删除项目：

SortedList

BTW：您不需要检查ObservableList<TestSuiteDetail> modifiableSource = ... FilteredList<TestSuiteDetail> filteredList = new FilteredList<(modifiableSource); SortedList<TestSuiteDetail> sortedList = new SortedList<>(filteredList); ... modifiableSource.removeAll(selectedItems); suiteCasesSelected.getSelectionModel().getSelectedItems()的结果，因为这总是会返回null，但{{1}可能是空的......

JavaFX 8：TableView过滤＆amp;行删除

2 个答案: