Question

我有这个游戏点数表，每个点都在列表中有4列：谁拥有它，在哪个游戏中，在哪个时期，以及游戏的日期。

我无法理解如何计算每位玩家在每场比赛中获得的积分数。我也想把它们按照游戏日和时期（第一和第二）的顺序排列。

到目前为止，我已经尝试过这个：

SELECT 
    SUM(POINTS) 
FROM 
    (SELECT POINTS, PERIOD 
     FROM POINTS_17 
     WHERE NAME = "player") 
WHERE 
    DISTINCT PERIOD ORDER BY DATE, PERIOD.

有关如何执行此操作或从何处开始的任何提示？还是可以的？

Answer 1

一些意见：

1）使用单引号，而不是双引号。

2）您的问题意味着分组，但要求对无法分组的列进行排序。

3）我已经包含了一些可能回答你问题的疑问。

4）前三个查询显示特定玩家的统计数据。最后三个查询显示每个玩家的统计数据相同。

-- Show a player's stats, ordered by date and period (like you asked). Since there is only one record per date/period, you don't need to SUM the values.
SELECT DATE, PERIOD, POINTS
FROM POINTS_17
WHERE NAME = 'player'
ORDER BY DATE, PERIOD;

-- Get the total and average points per period for a particular player (1st and 2nd period showed separately)
SELECT PERIOD, SUM(POINTS) AS TOTAL_POINTS, AVG(POINTS+0.0) AVERAGE_POINTS, COUNT(*) TOTAL_PERIODS
FROM POINTS_17
WHERE NAME = 'player'
GROUP BY PERIOD
ORDER BY PERIOD;

-- Get the total and average points per period for a particular player
SELECT SUM(POINTS) AS TOTAL_POINTS, AVG(POINTS+0.0) AVERAGE_POINTS, COUNT(*) TOTAL_PERIODS
FROM POINTS_17
WHERE NAME = 'player';




-- Show each player's stats, ordered by date and period.
SELECT NAME, DATE, PERIOD, POINTS
FROM POINTS_17
ORDER BY NAME, DATE, PERIOD;

-- Get the total and average points per period for every player (1st and 2nd period showed separately)
SELECT NAME, PERIOD, SUM(POINTS) AS TOTAL_POINTS, AVG(POINTS+0.0) AVERAGE_POINTS, COUNT(*) TOTAL_PERIODS
FROM POINTS_17
GROUP BY NAME, PERIOD
ORDER BY NAME, PERIOD;

-- Get the total and average points per period for every player
SELECT NAME, SUM(POINTS) AS TOTAL_POINTS, AVG(POINTS+0.0) AVERAGE_POINTS, COUNT(*) TOTAL_PERIODS
FROM POINTS_17
GROUP BY NAME;

SQL计数玩家周期点

1 个答案: