Question

我有一个像这样的mySQL DB架构：

table RECIPES:

int id, PK;
int salesman_id;
int doctor_id;
date order_date;
int status;

table RECIPE_STATUS:

int id, PK;
int recipe_status_code;
varchar recipe_status_name;

在Laravel中我有以下php类：

AdminRecipesController.php

namespace RatCMS\Controllers;

use App\Http\Controllers\Controller;
use Auth;
use RatCMS\Models\Recipes;
use RatCMS\Models\RecipeStatus;
use Illuminate\Http\Request;
use Illuminate\Support\Facades\Input;

class AdminRecipesController extends Controller
{
   
    public function index()
    {

        $recipes = Recipes::with('recipeStatus')->get();
        
        return view('admin.recipes.news', compact('recipes'));

    }

}



Recipes.php


<?php

namespace RatCMS\Models;

use Illuminate\Database\Eloquent\Model;


class Recipes extends Model
{

    protected $table = 'RECIPES';

    protected $fillable = ['salesman_id', 'doctor_id', 'order_date', 'status'];

    public function recipeStatus() {
        return $this->hasOne(\RatCMS\Models\RecipeStatus::class, 'recipe_status_code', 'status');
    }

}



RecipeStatus.php


<?php

namespace RatCMS\Models;

use Illuminate\Database\Eloquent\Model;

class RecipeStatus extends Model
{

    protected $table = 'RECIPE_STATUS';

    protected $fillable = [];

    public function recipes() {
        return $this->belongsTo(\RatCMS\Models\Recipes::class);
    }

}


blade view

<div class="box-body">
            @include('admin.partials.session_success')

            @if($recipes->isEmpty())
                <p class="text-center">No recipes available.</p>
            @else

                <table class="table table-bordered">
                    <tr>
                        <th style="width: 10px">#</th>
                        <th>Salesman</th>
                        <th>Doctor</th>
                        <th>Date</th>
                        <th>Status</th>
                        <th style="width:100px">Actions</th>
                    </tr>

                    @foreach($recipes as $recipe)
                        {{ $recipe }}
                        <tr>
                            <td>{{ $recipe->id }}</td>
                            <td>{{ $recipe->salesman_id }}</td>
                            <td>{{ $recipe->doctor_id }}</td>
                            <td>{{ $recipe->order_date }}</td>
                            <td>{{ $recipe->recipe_status->recipe_status_name }}</td>
                            <td>
                                <form style="display: inline-block" action="{{ url('admin/recipes/' . $recipe->id) }}" method="POST">
                                    {{ csrf_field() }}
                                    <input name="_method" type="hidden" value="DELETE">
                                    <button type="submit" class="btn btn-danger"><i class="fa fa-close" aria-hidden="true"></i> Delete</button>
                                </form>
                            </td>
                        </tr>
                    @endforeach
                </table>

            @endif


        </div>

当我在视图中执行{{ $recipe }}时，我得到以下结果：

{ “ID”：1， “salesman_id”： “4”， “doctor_id”： “3”， “order_date的”：NULL， “状态”： “0”， “recipe_status”：{ “ID”：1 ，“recipe_status_code”：“0”，“recipe_status_name”：“未收到”}}

所以有一些数据由Eloquent返回有关配方状态（未接收的文本），但是当我{{ $recipe->recipe_status }}时它每次都失败。甚至$ recipes ['recipe_status']都没有帮助。

有人可以帮忙吗？感谢

Answer 1

关系应为belongsTo()：

public function recipeStatus() {
    return $this->belongsTo(\RatCMS\Models\RecipeStatus::class, 'status', 'recipe_status_code');
}

如果关系正确，您的代码会将关系数据添加到集合中，这样您就可以获得状态：

$recipe->recipeStatus->recipe_status_name

Laravel：Eloquent返回一个我无法迭代的对象

1 个答案: