Question

我正在运行MSSQL Server 2016 Express。我想选择具有特定articlegroup_id值的所有行，并选择具有匹配articleid值的行。

因此，使用下面的数据，假设我想获得值为684的articlegroup_id的结果集。只有articleid的3107196和3100000匹配。所以结果集将是：

3100000 129
3100000 144
3100000 684
3107196 129
3107196 144
3107196 684

同样，如果我在articlegroup_id上运行相同的查询，其值为112，我想得到：

2106543 110
2106543 112
2106999 110
2106999 112

DDL

CREATE TABLE [dbo].[products_category_mapping](
    [articleid] [int] NOT NULL,
    [articlegroup_id] [int] NOT NULL
) ON [PRIMARY]

INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (3100000,129)
INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (3100000,144)
INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (3100000,684)

INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (3107196,129)
INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (3107196,144)
INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (3107196,684)

INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (3107100,129)
INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (3107100,144)

INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (2106543,110)
INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (2106543,112)

INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (2107000,110)

INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (2106999,110)
INSERT INTO products_category_mapping(articleid,articlegroup_id) VALUES (2106999,112)

Answer 1

另一种方法是使用JOIN

Select A.*
 From  [products_category_mapping] A
 Join (
        Select articleid from [products_category_mapping] where articlegroup_id=684
      ) B on A.articleid=B.articleid

Answer 2

您可以使用子查询查找给定articlegroupid的articleids，然后获取具有匹配的articleids的所有行

select * 
from products_category_mapping
where articleid in (
    select articleid
    from products_category_mapping
    where articlegroup_id = 684
)

另一种方法是使用join：

select p1.* 
from products_category_mapping p1
inner join products_category_mapping p2
on p1.articleid = p2.articleid
and p2.articlegroup_id = 684;

Answer 3

这是一种方法：

DECLARE @articlegroup_id int = 112 
;WITH CTE 
AS
(
    SELECT articleid
    FROM products_category_mapping
    WHERE articlegroup_id = @articlegroup_id
)

SELECT articleid, articlegroup_id
FROM products_category_mapping main
WHERE EXISTS (
    SELECT 1
    FROM CTE 
    WHERE CTE.articleid = main.articleid
    )

结果：

articleid   articlegroup_id
2106543     110
2106543     112
2106999     110
2106999     112

Answer 4

首先，没有名为SQL Server 2015

的版本

关于解决方案，请在where子句中使用子查询，如下所示： -

select * from [products_category_mapping]
where articleid in (
    select articleid 
    from [products_category_mapping] where articlegroup_id  = 684)

<强>结果： -

Answer 5

你可以使用exists来做这些：

select * products_category_mapping products1
where exists (select null from products_category_mapping products2
where products1.articleid = products2.articleid
and products2.articlegroup_id = 684);

TSQL：选择共享单个列值的行集

5 个答案: