Question

我正在尝试编写客户端 - 服务器代码。我在客户端代码中添加了一个菜单。根据客户端的输入，我尝试在服务器代码中添加案例。我能够将客户端选择的选项发送到服务器代码，但无法从接收的数据中选择案例。这是我的代码。

server.py

[sys_]name_to_handle_at()

Client.py

import socket

import sys

import os

s1 = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

print (' socket created s1')    

serveraddress = ('localhost' , 2000)

print ('starting server on', serveraddress)

s1.bind(serveraddress)

s1.listen(3)

while True:

    print('waiting for connection')

    connection, clientaddress = s1.accept()

    print ('connecting with', clientaddress)

    command = connection.recv(1000)

    print (command)

    if command == '1':

        print('entered into 1st if')

        try:

            filename = connection.recv(1000)

            with open(filename, 'rb') as filetosend:

                for data in filetosend:

                    connection.sendall(data)

        finally:

            connection.close()

    if command == '2':

        print('entered into 2st if')

        filelist = os.listdir('C:\Rahul')

        connection.sendall(filelist)

    if command == '3':

        print('entered into 3st if')

        s1.close()

        break

Answer 1

尝试在客户端脚本中添加除块以外的代码，之后您的代码将起作用。我建议你在套接字中使用raw_input作为输入，并在输入时格式化数据类型以避免程序中的任何错误。

import sys, os, socket s1 = socket.socket(socket.AF_INET, socket.SOCK_STREAM) serveraddress = ('localhost' , 2000) print ('connecting to server on'), serveraddress s1.connect(serveraddress) try: a = int(raw_input('Enter you choice: \n 1-Get file \n 2-Get List \n 3-quit \n')) while True: if a == 1: s1.send('1') b = str(raw_input('enter file name: ')) s1.send(b) # downloadDir = '\\root\\' # with open(os.path.join(downloadDir, b), 'wb') as filetowrite: # while True: # data = s1.recv(1000) # if not data: # break # filetowrite.write(data) # filetowrite.close() print "It worked till here." s1.close() elif a == 2: # s1.send('2') # #s1.sendall(' send all files list ') # filelist = s1.recv(1000) # print (filelist) print "It also worked till here." elif a == 3: x = False print "Closing Connection" s1.close() except: print 'It Gave an Error'

这很好。

无法读取客户端程序的输入

1 个答案: