我想在位置ID列表和一个位置ID之间进行比较。实际上我想说的是，如果值'000000'应该显示在位置ID [000000, 000000, 000000, 000000, 000000]列表的每个实例中。我可以让它为列表的一个实例工作，但我如何检查所有实例？目前它正在检查一个实例，但我需要检查整个列表。
下面是groovy代码：
import groovy.json.JsonSlurper
def response = messageExchange.response.responseContent
def json = new JsonSlurper().parseText(response)
def location_id = json.reviews.location_id
assert location_id != null
def location_id_response = location_id[0].toString()
def location_id_request = messageExchange.modelItem.testStep.testCase.getPropertyValue("locationid")
assert location_id_response == location_id_request
log.info location_id_request
log.info location_id_response
log.info location_id
以下是日志信息：
log.info location_id_request = '000000'
log.info location_id_response = '000000'
log.info location_id = [000000, 000000, 000000, 000000, 000000]
实际上location_id_response[0]正在从列表中选择第一个值，但我希望列表中包含location_id_request的所有值与列表中的每个值进行比较，而不仅仅是第一个值。如果我删除了＆＃39; 0＆＃39; 0从[0]开始，它会抛出一个数组错误。
答案 0 :(得分：1)
你只需要
assert location_id.every { it == location_id_request }
或者
assert location_id == [location_id_request] * location_id.size()
或者
assert location_id.distinct() == [location_id_request]
或者
assert location_id.distinct().with { it.head() == location_id_request && it.size() == 1 }