我是编写代码的整个OOP JavaScript风格的新手,所以我正在努力学习它以适应潮流。
我写了一个简单的函数,我试图利用原型和function Person(name, age, height, weight, IQ, ethnicity){
this.fullName = name;
this.age = age;
this.height = height;
this.weight = weight;
this.IQ = IQ;
this.ethnicity = ethnicity;
}
let Jou = new Person("Joseph", 21, 191, 78, 131, "caucasian");
let Franc = new Person("Francois", 13, 178, 50, 125, "caucasian");
let Svata = new Person("Svatopluk", 61, 188, 85, 140, "caucasian");
let names= ["Jou", "Franc", "Svata"];
let text = "";
for (let i = 0; i < names.lenght; i++){
text += names[i].fullName + " is " + names[i].age + " years old, "
+ names[i].height + "cm tall, weighs approximately "
+ names[i].weight + "kg, his IQ is around " + names[i].IQ +
" and he belongs to the " + names[i].ethnicity.toUpperCase() +
" ethnicity." + "<br>" ;
}
document.getElementById("name").innerHTML = text;
。看下面是:
<p id="name"></p>
我将其插入:df = pd.DataFrame({'ID':[1,1,2,2,3,3],
'YEAR' : [2011,2012,2012,2013,2013,2014],
'V': [0,1,1,0,1,0],
'C':[00,11,22,33,44,55]})
任何人都可以给我一些指示,关于我缺少什么,所以我可以学习如何使用它?
谢谢, Ĵ
答案 0 :(得分:2)
names
数组包含字符串,而不是实际变量。你应该删除双引号。此外,names.lenght
应为names.length
。
function Person(name, age, height, weight, IQ, ethnicity){
this.fullName = name;
this.age = age;
this.height = height;
this.weight = weight;
this.IQ = IQ;
this.ethnicity = ethnicity;
}
let Jou = new Person("Joseph", 21, 191, 78, 131, "caucasian");
let Franc = new Person("Francois", 13, 178, 50, 125, "caucasian");
let Svata = new Person("Svatopluk", 61, 188, 85, 140, "caucasian");
let names= [Jou, Franc, Svata];
let text = "";
for (let i = 0; i < names.length; i++){
text += names[i].fullName + " is " + names[i].age + " years old, "
+ names[i].height + "cm tall, weighs approximately "
+ names[i].weight + "kg, his IQ is around " + names[i].IQ +
" and he belongs to the " + names[i].ethnicity.toUpperCase() +
" ethnicity." + "<br>" ;
}
document.getElementById("name").innerHTML = text;
&#13;
<div id="name"></div>
&#13;
答案 1 :(得分:0)
你已经在字符串中包含了变量名,而你应该将它们作为变量引用,而不是字符串,所以改变它:
let names= ["Jou", "Franc", "Svata"];
到此:
let names= [Jou, Franc, Svata];
此外,你有一个拼写错误,这就是你的原始let names= [Jou, Franc, Svata];
无效的原因,所以改变
names.lenght
^^^
到
names.length
^^^