Question

我想要更改当前日期，或者我想把变量放在当前日期，如下所示：

$companyDates = $company_dates['dates']; //this variable come from DataBase
$databaseDate=DateTime::createFromFormat("Y-m-d", $companyDates);
$day=$databaseDate->format('d'); // this is how i take just days from date format(y-m-d)

$dt = new DateTime();
$today = $dt->format('Y-m-d');
$oldDate=$dt->format('Y-m-$day'); // here i want days from database into current day month and year.

然后我想找到这样的不同日子：

$date1=date_create($today);
$date2=date_create($oldDate);
$diff=date_diff($date1,$date2);

这可能吗？或者这是我的方式吗？

Answer 1

您正试图在格式

中传递所需的日期

$oldDate=$dt->format('Y-m-$day');

格式错误（如果要将字符串与变量连接起来，则应使用双quote(")代替single(')）

使用setDate()方法代替。

$today = new DateTime();
$oldDate = clone $today; // Clone instead creating new instance because two different DateTime instances may have different dates
$oldDate->setDate($oldDate->format('Y'), $oldDate->format('m'), $day);

Answer 2

试试这个：使用setDate

$day=10;
$dt = new DateTime();
$today = $dt->format('Y-m-d');
$out = new DateTime();
$out->setDate($out->format('Y'), $out->format('m'), $day);
$oldDate= $out->format('Y-m-d');
$d1=new DateTime($oldDate);$d2=new DateTime($today);
$difference = $d1->diff($d2);
echo $difference->format('%r%a days');

我如何才能改变当前日期而不仅仅是几天？

2 个答案: