Question

这个问题是What is the most efficient way to extract info from complex JSON files?

的后续问题

我有大量的dict文件，其结构可以是任意的。我希望使用＆＃34; text，＆＃34;的键来捕获所有字符串。以及带有＆＃34; htext＆＃34;键的所有字符串;当没有额外的巢。

["today", "yesterday", "a", "b", "c", "tomorrow"]

在上面的示例中，我希望我的结果为def extract_text(obj, acc): if isinstance(obj, dict): for k, v in obj.items(): if isinstance(v, (dict, list)): extract_text(v, acc) elif k == "text": acc.append(v) elif isinstance(obj, list): for item in obj: extract_text(item, acc)。

上一个问题中提供的解决方案是：

k == 'htext'

我尝试通过将elif添加到file_get_contents语句来修改此功能，但未成功。我是Python的新手。非常感谢任何帮助！

Answer 1

试试这个：

d = {
        "section": {
                   "heading":{"lvl":"A1", "text":"today"},
                   "htext":[
                                {"color":"green",  "text":"yesterday", "htext":["a","b","c"]},
                                {"color":"purple", "text":"tomorrow"}
                               ]
                   }
         }

acc = [];

def extract_text(obj, acc):
     if isinstance(obj, dict):
         for k, v in obj.items():
             if isinstance(v, dict):
                 extract_text(v, acc)
             elif k == "text":
                 acc.append(v)
             elif k == "htext" and isinstance(v, list) and all([isinstance(item, str) for item in v]):
                 for item in v:
                     acc.append(item)
             elif isinstance(v, list):
                 extract_text(v, acc)
     elif isinstance(obj, list):
         for item in obj:
             extract_text(item, acc)


extract_text(d, acc)
print(acc)

Answer 2

您可以检查密钥是否为＆＃34; htext＆＃34;并且值是非嵌套列表：

def extract_text(obj, acc):
    if isinstance(obj, dict):
        for k, v in obj.items():
          if k == "htext" and isinstance(v, list) and not isinstance(v[0], (dict, list)):
             for x in v:
               acc.append(x) 
          elif isinstance(v, (dict, list)):
              extract_text(v, acc)
          elif k == "text":
              acc.append(v)

    elif isinstance(obj, list):
        for item in obj:
            extract_text(item, acc)

#=> ['yesterday', 'a', 'b', 'c', 'tomorrow', 'today']

如何从嵌套的dict文件的最深层提取文本？

2 个答案: