我有一个我无法工作的脚本。我一直收到错误'Geocoder failed'但我不确定为什么。它应该得到long / lat然后反向地理编码它以在警告框中显示街道地址。我已经尝试确保浏览器让它共享该位置。我也尝试过通过HTTPS访问,因为我读到现在需要它,但它仍然无效。 如果有人能帮助我完成这项工作,我将非常感激! 提前谢谢。
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Current Location Address</title>
<style>
</style>
</head>
<script type="text/javascript" src="https://maps.googleapis.com/maps/api/js?sensor=false"></script>
<script type="text/javascript">
var geocoder;
if (navigator.geolocation) {
navigator.geolocation.getCurrentPosition(successFunction, errorFunction);
}
//Get the latitude and the longitude;
function successFunction(position) {
var lat = position.coords.latitude;
var lng = position.coords.longitude;
codeLatLng(lat, lng)
}
function errorFunction(){
alert("Geocoder failed");
}
function initialize() {
geocoder = new google.maps.Geocoder();
}
function codeLatLng(lat, lng) {
var latlng = new google.maps.LatLng(lat, lng);
geocoder.geocode({'latLng': latlng}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
console.log(results)
if (results[1]) {
//formatted address
alert(results[0].formatted_address)
//find country name
for (var i=0; i<results[0].address_components.length; i++) {
for (var b=0;b<results[0].address_components[i].types.length;b++) {
//there are different types that might hold a city admin_area_lvl_1 usually does in come cases looking for sublocality type will be more appropriate
if (results[0].address_components[i].types[b] == "administrative_area_level_1") {
//this is the object you are looking for
city= results[0].address_components[i];
break;
}
}
}
//city data
alert(city.short_name + " " + city.long_name)
} else {
alert("No results found");
}
} else {
alert("Geocoder failed due to: " + status);
}
});
}
</script>
</head>
<body onload="initialize()"> <font face="verdana">
<!DOCTYPE html>
If available, your current address will have been displayed in a message window. Please press 'Back' when finished.
</body>
</html>
答案 0 :(得分:0)
您的errorFunction
会自动传递error
参数,您可以查看该参数:
function errorFunction(error){
alert("Geocoder failed: "+error.message);
}
有关更多背景和示例,请参阅the MDN docs。