Question

这是我的代码我不知道我做错了什么。所有的问题都在功能史上。 LebelText是一个定时器计时器标签，由另一个视图控制器进行调整。所以我想把lebetText转换为int来从中减去1，然后将其重新转换回字符串以显示数字。

这是视图控制器a。被塞住的短信是lebelText。

 import UIKit

class testViewController: UIViewController {

@IBOutlet var lazel: UILabel!

@IBOutlet var plax: UIButton!
@IBOutlet var stopx: UIButton!

var timer = Timer()
var counter = 0.0
var isRunning = false


override func viewDidLoad() {
    super.viewDidLoad()





}

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    let DestViewController : restultViewController = segue.destination as! restultViewController

    DestViewController.LebelText = lazel.text!

}
@IBAction func play(_ sender: Any) {

   if !isRunning{
    timer = Timer.scheduledTimer(timeInterval: 0.1, target: self, selector: #selector(testViewController.update), userInfo: nil, repeats: true)
 }
    plax.isEnabled = false
    stopx.isEnabled = true

        }

 @IBAction func stop(_ sender: Any) {

    plax.isEnabled = true
    stopx.isEnabled = false
    timer.invalidate()
    isRunning = false


   }


   func update(){
    counter += 0.1
    lazel.text = String(format: "1%f", counter)
    lazel.text = "\(counter)"


    }}

这是视图控制器b。目标是将lebelText转换为int，从中减去1。然后将其转换回字符串，以便显示。

   import UIKit
   class restultViewController: UIViewController {

   @IBOutlet var dxe: UILabel!


    var LebelText = String()

    let myInt = Int()

   override func viewDidLoad() {
   super.viewDidLoad()
  steve()

   }
  func steve(){

var eq = LebelText

var intValue = Int(eq)

let vx = intValue! - 1
let ramit = String(vx)
dxe.text = ramit
  }

Answer 1

好的，以便摆脱可选项，并确保它应该像

一样

if let intValue = Int(eq) {
     vx = intValue - 1
     dxe.text = String(vx)
} else {
     //do some stuff if you  cannot convert eq to Int
}

但我建议你从一些更简单的任务开始，看起来你没有完全学习基础知识。

import UIKit
class restultViewController: UIViewController {

    @IBOutlet var someLabel: UILabel!
    public var myText: String?

    override func viewDidLoad() {
       super.viewDidLoad()
       self.parseData()
    }

    private func parseData(){
        guard let unwrapedText = self.myText else {
            //you didn't pass string
            return
        }
        if let myInt = Int(unwrapedText) {
            myInt = myInt - 1 
            self.someLabel.text = String(myInt)
        } else {
            //you string is not convertable to int
        }
    }
}

Answer 2

你可以这样做。

import UIKit
   class restultViewController: UIViewController {

   @IBOutlet var dxe: UILabel!


    var LebelText = String()

    let myInt = Int()

   override func viewDidLoad() {
   super.viewDidLoad()
  steve()

   }
  func steve(){

var eq = Int(LebelText.text)

eq = eq - 1

dxe.text = String(eq)
  }

解包一个被破坏的字符串时出现致命错误（swift3）

2 个答案: