Question

print("welcome to the password reset program")
print("please enter the new password")
input("type your new password")
input("type your new password (8-16 characters)")
password = input("type your new password (8-16 characters)")
    if password == <8
        print("this is too short, rethink, and re-enter your new password...")
    if password == >16
        print("this is too long, rethink, and re-enter your new password...")
    if password == 8-16
        print("this is the correct length, now re-enter to confirm")
password2 = input("re-enter your password")
    if password == password2
        print("your password has been changed")
    if password != password2
        print("this is not the same as your first password")

我收到错误“if password ==＆lt; 8” 你可以帮我吗????

Answer 1

您需要使用len()来比较密码的长度。

您还需要使用<或<=来比较它而不是==，并在if语句的末尾添加一个冒号。

所以你的代码看起来像是：

if len(password) <= 8:
    print("this is too short, rethink, and re-enter your new password...")
if len(password) >=16:
    print("this is too long, rethink, and re-enter your new password...")

你可以简化为

if len(password) <= 8 or len(password) >= 16:
    print("Password must be between 8 and 16 characters, enter your new password...")

要让用户重新输入密码，您可以使用while循环直到他们的输入有效：

while(len(password) <= 8 or len(password) >= 16):
    print("Password must be between 8 and 16 characters, enter your new password...")
    password=input("type your new password")

您可以再次使用它来检查用户输入相同的密码：

password2 = input("re-enter your password")
while password2!=password:
     password2=input("this is not the same as your first password")
print("your password has been changed")

正如其他用户所提到的，你应该看看哈希： LxLite

Answer 2

首先，没有＆＃39; x ==＆lt; ý＆＃39 ;.您正在寻找＆＃39; x＆lt; = y＆＃39;。

其次，正如我之前的答案中所述，你必须添加＆＃39;：＆＃39;在if之后。

你应该阅读文档。

Answer 3

print("welcome to the password reset program")
print("please enter the new password")
input("type your new password")
input("type your new password (8-16 characters)")
password = input("type your new password (8-16 characters)")
if len(password) <= 8:
    print("this is too short, rethink, and re-enter your new password...")
elif len(password) >= 16:
    print("this is too long, rethink, and re-enter your new password...")
else:
    print("this is the correct length, now re-enter to confirm")
    password2 = input("re-enter your password")
    if password == password2:
        print("your password has been changed")
    else:
        print("this is not the same as your first password")

正如其他人所建议我在python中阅读有关缩进的文档以及如何使用if / else。

Answer 4

您的代码存在一些问题，我猜测您可能来自JavaScript背景。

问题如下。

您遗漏了:声明末尾的if。
您无法在Python中使用== <或== >正确使用<=和>=。
您的if语句也有不正确的缩进。

以下更新的代码。

print("welcome to the password reset program")
print("please enter the new password")
input("type your new password")
input("type your new password (8-16 characters)")
password = input("type your new password (8-16 characters)")
if len(password) <= 8:
    print("this is too short, rethink, and re-enter your new password...")
if len(password) >= 16:
    print("this is too long, rethink, and re-enter your new password...")
if len(password) == (8-16): # is this a range or 8 - 16?
    print("this is the correct length, now re-enter to confirm")
password2 = input("re-enter your password")
if password == password2:
    print("your password has been changed")
if password != password2:
    print("this is not the same as your first password")

不要忘记哈希密码。https://docs.python.org/3/library/hashlib.html

Answer 5

您需要在每个if，for或while语句后添加:。
运营商== <或== >不存在，您可以使用=>或<=代替
在此行中：if password == 8-16您可以使用运算符in来评估变量是否在列表中，并将其作为if len(password) in range(8-16)

在你的情况下可能是

if password <= 8
        print("this is too short, rethink, and re-enter your new password...")
    if password >= 16
        print("this is too long, rethink, and re-enter your new password...")
    if len(password) in range(8, 16)
        print("this is the correct length, now re-enter to confirm")
password2 = input("re-enter your password")
    if password == password2
        print("your password has been changed")
    if password != password2
        print("this is not the same as your first password")

我如何使这项工作？我不断收到语法错误

5 个答案: