Question

我目前正在使用Spyder IDE。我正在尝试将基于不同组的自编译函数 sfill 应用于我的数据框。每当我创建此函数时，我都会收到以下错误：

TypeError：sfill（）只取1个参数（给定2个）

我确定 sfill（） 功能在独立运行时可以正常工作。我究竟做错了什么？如何在不使用变量资源管理器中的语句 全局需要 的情况下，允许Python显示数据框想要？如何在此瞬间使用return？

我的代码如下：

import pandas as pd
have = pd.DataFrame({ \
"groups": pd.Series(["group1","group1","group1","group2","group2","group2"]) \
,"a0": pd.Series(["abc","1","something here","abc2","1","something here"]) \
,"a1": pd.Series(["","2","something here","","","something here"]) \
,"a2": pd.Series(["","3","something here","","3","something here"]) \
,"a3": pd.Series(["something","1","something here","something","1","something here"]) \
,"a4": pd.Series(["","2","something here","","2","something here"]) \
,"a5": pd.Series(["","","something here","","","something here"]) \
,"a6": pd.Series(["","","something here","","","something here"]) \
,"a7": pd.Series(["cdf","5","something here","mnop","5","something here"]) \
,"a8": pd.Series(["","6","something here","","6","something here"]) \
,"a9": pd.Series(["xyz","1","something here","xyz","1","something here"]) \
})

class main(object):
    def sfill(vector):
        vector = vector.copy()
        vector.i0, vector.i1 = vector.index[0], vector.index[1]
        vector.cond = have.loc[vector.i1].ne('') 
        vector.loc[vector.i0, vector.cond] = vector.loc[vector.i0, vector.cond].str.strip().replace('', None)
        return vector

    def Development_plan(selfdev):
        global want
        want=have.groupby('groups', group_keys=False, sort=False).apply(selfdev.sfill)



a=main()
a.Development_plan() # this is where the issue exists

感谢。

Answer 1

类中的函数应该以{{1}}作为第一个参数

self

当您致电def sfill(self, vector): ...时，它实际上会调用selfdev.sfill(soemthing)

sfill(selfdev, something)只是一个命名约定，在您的Development_plan（）中使用selfdev。

Python pandas应用在类中定义的函数

1 个答案: