Question

我是宁静服务的新手，我一直在创建一系列简单的控制台应用程序，以便更好地理解。我有一个simlple服务，我正在尝试发送数据，但我不断收到400错误的请求错误。我知道它必须是我忽略的简单事物。任何帮助将不胜感激。感谢

//service contract
[OperationContract, WebInvoke(Method = "POST", UriTemplate = "Test")]
bool Test(string input);

//service
public bool Test(string input)
{
   Console.Out.WriteLine("recieved [" + input + "]");
   return true;
}

//host program
class Program
{
    static void Main(string[] args)
    {
        Uri baseAddress = new Uri("http://localhost:8889/TestImage");
        WebServiceHost host = new WebServiceHost(typeof(ImageTestService), baseAddress);

        try   
        {   
            host.Open();

            Console.Out.WriteLine("TestService hosted at {0}", baseAddress.ToString());
            Console.Out.WriteLine("hit enter to terminate");
            Console.In.ReadLine();
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex.Message);
            Console.ReadKey();
        }
        finally
        {
            if (host.State == CommunicationState.Faulted)
                host.Abort();
            else
                host.Close();
        }   
    }
}

//client program
// Create the web request
Uri address = new Uri("http://localhost:8889/TestImage/Test");
HttpWebRequest request = WebRequest.Create(address) as HttpWebRequest;

// Set type to POST   
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";

StringBuilder data = new StringBuilder();
data.Append("input=" + HttpUtility.UrlEncode("12345"));

// Create a byte array of the data we want to send   
byte[] byteData = UTF8Encoding.UTF8.GetBytes(data.ToString());

// Set the content length in the request headers   
request.ContentLength = byteData.Length;

// Write data   
using (Stream postStream = request.GetRequestStream())
{
   postStream.Write(byteData, 0, byteData.Length);
   postStream.Close();
}

// Get response   
using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
{
   // Get the response stream   
   StreamReader reader = new StreamReader(response.GetResponseStream());
}

Answer 1

不确定这是您的问题的答案 - 但我有一个我一直用于表单发布的扩展方法：

    public static HttpWebResponse DoFormPost(this HttpWebRequest request, string postVals, int timeoutSeconds)
    {
        request.Method = "POST";
        request.Timeout = timeoutSeconds * 0x3e8;
        request.ContentType = "application/x-www-form-urlencoded";
        request.AllowAutoRedirect = false;
        byte[] bytes = Encoding.UTF8.GetBytes(postVals);
        request.ContentLength = bytes.Length;
        using (Stream stream = request.GetRequestStream())
        {
            stream.Write(bytes, 0, bytes.Length);
        }
        return (HttpWebResponse)request.GetResponse();
    }

或者，既然您标记了WCF，那么还有另一个类似的问题：

Getting an http 400 error on calling a restful wcf service using http post

Answer 2

不幸的是，我不确定你的代码有什么问题，乍一看似乎没问题。我想知道你使用的是UriTemplate。如果您的方法是“Test”且UriTemplate是“Test”，您可能需要使用此URL（两个“Test”字符串）调用它：

Uri address = new Uri("http://localhost:8889/TestImage/Test/Test");

我认为默认情况下方法名称是URL的一部分，因此在此之后应用模板。

对于HTTP错误，我使用名为Fiddler的工具进行故障排除。如果您可以创建一个与Request Builder一起使用的请求，那么只需要弄清楚如何通过您的代码生成该请求。

Answer 3

您正在调用的WCF服务期望您传递的字符串以XML格式化！

以下对我有用：

string body = "foo";
string postData = @"<string xmlns='http://schemas.microsoft.com/2003/10/Serialization/'><![CDATA[" + body + "]]></string>";

帮助简单的休息帖子问题

3 个答案: