在react-native中设置redux-persist时出错

Question

我正在尝试在已经使用redux的react-native项目中设置redux-persist。我不能让它工作。

我遵循了这篇文章：https://medium.com/differential/building-offline-first-react-native-apps-b958acac0009#.vmshi0cxk

这是我在app.js中的设置：

import React, {Component} from 'react';
import { Navigator, View, StyleSheet } from 'react-native';
import { createStore, applyMiddleware, combineReducers } from 'redux';
import { Provider } from 'react-redux';
import thunk from 'redux-thunk';
import { persistStore, autoRehydrate } from 'redux-persist';

import * as reducers from '../reducers';

const createStoreWithMiddleware = applyMiddleware(thunk)(createStore);

configureStore = (onComplete) => {
    const store = autoRehydrate()(createStoreWithMiddleware)(reducers);
    persistStore(store, { storage: AsyncStorage }, onComplete);

    return store;
};

App的开头（在同一个文件中）：

class App extends Component {
    constructor(props) {
      super(props);
      this.state = {
        isLoading: true,
        store: configureStore(() => this.setState({ isLoading: false })),
      };
    }

    render() {
        if (this.state.isLoading) return null;
        ....
    }
}

尝试此操作时，我将“reducer is not function”视为错误。

在/ reducers文件夹中我有index.js：

import recordReducer from './recordReducer';

export {
  recordReducer
};

并在recordReducer.js中：

import * as types from '../actions/actionTypes';

const initialState = {};

export default function recordReducer(state = initialState, action = {}) {    
  switch (action.type) {
    case types.SAVE_RECORDING_SUCCESS:
      return {
        ...state,
        recordings: state.recordings ? state.recordings.concat([action.recording]) : [action.recording]
      };
    default:
      return state;
  }
}