Question

我刚刚编写了一些代码来将一个点列表转换为一个to / from元组的列表，但它感觉效率不高。

我想知道是否有人有任何建议让这更简洁？

from_point, to_point = None, None
point_list = []

for p in [1, 5, 2, 4, 7, 9]:
    to_point = p
    if from_point and to_point:
        point_list.append((from_point, to_point))
    from_point = to_point

print(point_list)

输入：[1, 5, 2, 4, 7, 9]

输出：[(1, 5), (5, 2), (2, 4), (4, 7), (7, 9)]

编辑：将点更改为非连续点。

Answer 1

您始终可以使用zip：

>>> p = [1, 5, 2, 4, 7, 9]
>>> point_list = list(zip(p[:-1], p[1:]))
>>> print(point_list)
[(1, 5), (5, 2), (2, 4), (4, 7), (7, 9)]

Answer 2

另一种单行解决方案

input = [1, 2, 3, 4, 5, 6]
output = [(input[index], input[index+1]) for index in range(len(list)-1)]
print(output)

Answer 3

这个怎么样？

x=[1, 5, 2, 4, 7, 9]
print [ tuple(x[i:i+2]) for i in xrange(len(x)-1) ]

Answer 4

使用more_itertools：

from yahoo_finance import Share

with open('positions.txt', 'r') as fp:
    result = fp.readlines()

for ticker in result:
    #the yahoo finance functions are below
    var2 = Share(ticker)
    print(var2.get_price())

将列表转换为python中的元组列表

4 个答案: