所有
说我有table1喜欢:
// Object for storing the clustered correspondences.
std::vector<pcl::Correspondences> clusteredCorrespondences;
// Object for storing the transformations (rotation plus translation).
std::vector<Eigen::Matrix4f, Eigen::aligned_allocator<Eigen::Matrix4f> > transformations;
并且table2是相同的结构,如何将它们的内容连接在一起并进行name|id|email
查询
由于
答案 0 :(得分:1)
您可以使用子查询:
SELECT * FROM (SELECT * FROM table1
UNION ALL
SELECT * FROM table2);
或公用表表达式:
WITH newbuildtable AS (
SELECT * FROM table1
UNION ALL
SELECT * FROM table2
)
SELECT * FROM newbuildtable;
或视图:
CREATE VIEW newbuildtable AS
SELECT * FROM table1
UNION ALL
SELECT * FROM table2;
SELECT * FROM newbuildtable;
如果您不想引用原始数据,请将所有数据复制到新表中:
CREATE TABLE newbuildtable AS
SELECT * FROM table1
UNION ALL
SELECT * FROM table2;
SELECT * FROM newbuildtable;