我有函数 getBoundedVars ,它使用函数 boundsInLambda 。最后,所有框 bBox 应包含表达式 exp 中的所有有界变量。 我正在尝试调试此函数,为了这样做,我想在每次激活函数时打印 boundsInLambda 的参数但由于某种原因,值不会显示在屏幕上。 如果我将显示操作放在 getBoundedVars 中,它将打印它,但这些只是第一次迭代中的值。
如果我运行以下内容:
(getBoundedVars(lambda-simple(x)(lambda-simple(y)(const x)))bx)
当bx是空盒子时,
将打印'1,但boundsInLambda中的打印命令将不会
这是代码:
(define getBoundedVars
(lambda (exp bBox)
(if (atom? exp)
0 ;; don't put in box
(if (lambda? (car exp))
(begin
(display 1)
(newline)
(let ((pBox (make-pBox exp))
(lBox (box '()))
(bodyExp (make-body exp))
)
(boundsInLambda bodyExp lBox pBox bBox)))
(begin
(getBoundedVars (car exp) bBox)
(getBoundedVars (cdr exp) bBox))))))
(define boundsInLambda
(lambda (bodyExp lastBox paramBox boundsBox)
(newline)
(display `(bodyExp: ,bodyExp))
(newline)
(display `(lastBox: ,lastBox))
(newline)
(display `(paramBox: ,paramBox))
(newline)
(display `(boundsBox: ,boundsBox))
(newline)
(if (and (not (null? bodyExp))
(list bodyExp)
(equal? (car bodyExp) 'seq)
)
(map boundsInLambda (cadr bodyExp))
(let* ( (lists* (filter (lambda (el) (and (not (null? el)) (list? el) (not (equal? (car el) 'const)))) bodyExp))
(lists (map (lambda (el) (if (equal? (car el) 'set) (cddr el) el)) lists*))
(bounds (filter (lambda (el) (and (member el (unbox lastBox)) (not (member el (unbox paramBox))))) bodyExp))
(listsLeft? (> (length lists) 0))
(anyBounds? (> (length bounds) 0))
)
(if anyBounds?
(begin
(set-box! boundsBox (append (unbox boundsBox) bounds))))
(if listsLeft?
(map
(lambda (lst)
(if (lambda? (car lst))
(let* ((newBodyExp (make-body lst))
(newParamBox (make-pBox exp))
(newLastBox (box (append (unbox lastBox) (unbox paramBox))))
)
(boundsInLambda newBodyExp newLastBox newParamBox boundsBox))
(boundsInLambda lst lastBox paramBox boundsBox)))
lists)
0))
)))
(define make-pBox
(lambda (lamExp)
(if (equal? (car lamExp) 'lambda-simple)
(box (cadr lamExp))
(if (equal? (car lamExp) 'lambda-opt)
(box (cadr lamExp))
(box '())))))
(define make-body
(lambda (lamExp)
(if (equal? (car lamExp) 'lambda-opt)
(cdddr lamExp)
(cddr lamExp))))
非常感谢任何帮助。