Question

我试图在同一个表之间运行内部联接。我的语法出了什么问题？

(SELECT user_key, bill_number, MAX(payment_date) AS payment_date 
 FROM billpayment) bpt 
 INNER JOIN (SELECT * FROM billpayment) bp
   ON bp.user_key=bpt.user_key 
   AND bp.bill_number=bpt.bill_number 
   AND bp.payment_date=bpt.payment_date 
 GROUP BY user_key, bill_number;

它表示sql命令没有在＆＃39; billpayment）的括号中正确结束＆＃39;

Answer 1

SELECT 
     user_key, 
     bill_number, 
     MAX(payment_date) AS payment_date 
    FROM billpayment bpt 
    INNER JOIN billpayment bp 
    ON bp.user_key=bpt.user_key 
    AND bp.bill_number=bpt.bill_number AND bp.payment_date=bpt.payment_date 
    GROUP BY 
     user_key, bill_number

;

Answer 2

On Oracle试试这个：

  SELECT *
    FROM (SELECT user_key, bill_number, MAX (payment_date) AS payment_date FROM billpayment) bpt
         INNER JOIN billpayment bp
            ON bp.user_key = bpt.user_key AND bp.bill_number = bpt.bill_number AND bp.payment_date = bpt.payment_date
    GROUP BY user_key, bill_number;

没有表结构就无法测试它。

Answer 3

如何使用分析函数？

select bp.*,
       max(bp.paymentdate) over (partition by user_key, bill_number) as max_payment_date
from billpayment

如果您想要最长付款日期的字段：

select bp.*
from (select bp.*,
             max(bp.paymentdate) over (partition by user_key, bill_number) as max_paymentdate
      from billpayment
     ) bp
where paymentdate = max_paymentdate;

Answer 4

在mySQL上，您可以尝试类似：

 SELECT bpt.user_key, bpt.bill_number, MAX(bpt.payment_date) AS payment_date 
 FROM billpayment bpt 
 INNER JOIN (SELECT * FROM billpayment) bp
   ON bp.user_key=bpt.user_key 
   AND bp.bill_number=bpt.bill_number 
   AND bp.payment_date=bpt.payment_date 
 GROUP BY bpt.user_key, bpt.bill_number;

内连接相同的表语法错误

4 个答案: