如何将df的每一行填充到左侧,并留出足够的空格以确保行总计30个字符?
我尝试沿着这条路走下去,但它没有用,我相信ljust
已被弃用:
'{: <30}'.format(df['test1'])
目前:
>>> df['test1']
0 1234jjjjjjjdddd
1 1234jjjjjjjdd
2 1234jjjjjjjddddddddd
3 1234jjjjjjjddd
4 1234jjjjjjjdddddd
我在寻找:
>>> df['test1']
0 1234jjjjjjjdddd
1 1234jjjjjjjdd
2 1234jjjjjjjddddddddd
3 1234jjjjjjjddd
4 1234jjjjjjjdddddd
最终解决方案:
df['test1'] = df.test1.str.rjust(30,' ')
答案 0 :(得分:3)
我认为您可以使用str.rjust
:
print (df.test1.str.rjust(30, ' '))
0 1234jjjjjjjdddd
1 1234jjjjjjjdd
2 1234jjjjjjjddddddddd
3 1234jjjjjjjddd
4 1234jjjjjjjdddddd
Name: test1, dtype: object
答案 1 :(得分:0)
这应该有效:
spaces = " " * 30
df['test1'] = [spaces[-len(i):] + i for i in df['test1']]