我正在寻找一种简洁的CSS解决方案来为元素的背景创建特定的模式。该图案是本页顶部带有红点的微小图案:
以上是放大的图像,因此更容易看到图案:
我只关心红点图案,而不是边框。
我尝试了很多变化,如下所示,但似乎无法解决它:
div {
background-image:
linear-gradient(-45deg, red 25%, transparent 25%),
linear-gradient(45deg, red 25%, transparent 25%),
linear-gradient(45deg, transparent 75%, red 75%),
linear-gradient(-45deg, transparent 75%, red 75%);
background-size: 2px 2px;
background-position: 40.5% 0, 40.5% 52%, 0 0, 0.05% 52%;
}
答案 0 :(得分:0)
我设法使用CSS伪造元素:before
和:after
来模拟模式,以及#34;覆盖"重复"棋盘的一部分"红色和白色背景。不幸的是,这要求您使用transparent
以外的颜色来表示"间隙"在红色,以便后面的瓷砖可以覆盖"红色的棋盘部件。
以下JsFiddle使用transform:scale(10)
来更好地显示模式,我不确定您是否打算将内容放在具有此背景的元素内,但我想表明psuedo元素位于任何后面内部内容,但以下代码只包含相关的css
.background {
height:100px;
width:100px;
position:relative;
background-image:linear-gradient(45deg, red 25%, transparent 25%, transparent 75%, red 75%, red),
linear-gradient(45deg, red 25%, white 25%, white 75%, red 75%, red);
background-size: 2px 2px;
background-position:0 0, 1px 1px;
}
.background:after,
.background:before{
content:"";
/* position the psuedo elements entirely over the background */
top:0;
left:0;
position:absolute;
height:100%;
width:100%;
/* create "cover" gradients */
background-image:linear-gradient(45deg, white 25%, transparent 25%);
background-size:4px 4px;
background-position:0 0;
background-repeat:repeat;
/* set a negative z-index so content is above it */
z-index:-1;
}
.background:before{
background-position:2px 2px;
}
<强>更新强>
从http://patternify.com/获取base64 png生成器代码并对设计进行硬编码,我们最终得到了JS,它将输出您需要制作html电子邮件背景图片拼贴的图像代码。您只需根据需要更改color1
和color2
变量。
<强> JSFIDDLE 强>
<强> JS 强>
//create a new canvas element to hold the sized down pattern
var output = document.getElementById('base64-code');
var patcanvas = document.createElement('canvas');
var patcontext = patcanvas.getContext('2d');
var color1 = [255,0,0,1]; // red
var color2 = [255,255,255,1]; // white
var matrix = [
[color2, color1, color2, color1],
[color1, color2, color2, color2],
[color2, color1, color2, color1],
[color2, color2, color1, color2]
];
/*
the matrix variable represents the width, then height of the pattern, so we're sort of drawing it on its side and mirrored
.#.#
#...
.#.#
..#.
will result in
.#..
#.#.
...#
#.#.
*/
function drawPattern() {
//set width and height, which also clears the canvas
patcanvas.width = 4;
patcanvas.height = 4;
for (var i = 0; i < matrix.length; i++) {
for (var j = 0; j < matrix[i].length; j++) {
if (matrix[i][j] != 0) {
tileColor = matrix[i][j];
patcontext.fillStyle = "rgba(" + tileColor[0] + ", " + tileColor[1] + ", " + tileColor[2] + ", " + tileColor[3] + ")";
patcontext.fillRect(i, j, 1, 1);
}
}
}
//get the preview canvas and clear it as well
var pcanvas = document.getElementById("preview-canvas");
pcanvas.width = pcanvas.width;
var pcontext = pcanvas.getContext("2d");
//create a pattern from the pattern canvas and fill the preview canvas with it
var pattern = pcontext.createPattern(patcanvas, "repeat");
pcontext.rect(0, 0, pcanvas.width, pcanvas.height);
pcontext.fillStyle = pattern;
pcontext.fill();
//also update the code
var dataURL = patcanvas.toDataURL("image/png");
output.innerHTML = dataURL;
};
drawPattern();
答案 1 :(得分:0)
虽然@haxxxton以他的回答超越了董事会并且我赞扬它,但我最终还是想出了如何用CSS做这件事。
它与样本背景图案完全匹配,并且很容易更改颜色。
以下是我提出的建议:
.background {
background-color: white;
background-image:
repeating-linear-gradient(-45deg, transparent, transparent 33%, red 0%, red 50%),
repeating-linear-gradient(-45deg, transparent, transparent 33%, white 0%, white 50%),
repeating-linear-gradient(-45deg, transparent, transparent 33%, white 0%, white 50%),
repeating-linear-gradient(45deg, transparent, transparent 33%, red 0%, red 50%);
background-size: 4px 4px;
background-position: -1px, 2px, 1px 1px;
}