Question

我正在尝试在我的应用中实施UNUserNotification。一般情况下它可以工作，但我需要用userInfo传递我的对象（后来才接收它）：

static func showNotification(_ serverNotification: ServerNotification){
    print("showNotification called")
    let content = UNMutableNotificationContent()
    content.title = serverNotification.title
    content.body = serverNotification.notificationDescription
    content.sound = UNNotificationSound.default()
    content.categoryIdentifier = "pl.tropicalapps.TryOnNotification"
    content.userInfo = ["serverNotification" : serverNotification]
    let trigger = UNTimeIntervalNotificationTrigger(timeInterval: 1, repeats: false)
    let request = UNNotificationRequest(identifier: "Request", content: content, trigger: trigger)
    let center = UNUserNotificationCenter.current()
    center.add(request) { (error:Error?) in
        if let err = error {
            print(err)
        }
        else{
            print("notification sent!")
        }
    }
}

如果我不添加userInfo或传递[“foo”：“bar”]，它就可以了。但是当我添加我的对象（serverNotification）时，它会在发送请求后崩溃。我无法捕捉到这个错误，但它出现在` - [NSXPCEncoder _checkObject：] :(其余的是汇编程序）。

这是ServerNotification类：

class ServerNotification : NSCoder {

    var id:Int
    var type:String
    var brandId:Int
    var title:String
    var notificationDescription:String = ""
    var discountId:String
    var discountPercent:Double
    var discountDescription:String
    var discountCode:String
    var discountType:String
    var discountExpireDate:Date
    var date:Date

    override init(){
        id = 0
        type = ""
        brandId = 0
        title = ""
        notificationDescription = ""
        discountId = ""
        discountPercent = 0.0
        discountDescription = ""
        discountCode = ""
        discountType = ""
        discountExpireDate = Date()
        date = Date()
    }

    required init(coder aDecoder: NSCoder) {
        id = aDecoder.decodeInteger(forKey: "id")
        type = aDecoder.decodeObject(forKey: "type") as! String
        brandId = aDecoder.decodeInteger(forKey: "brandId")
        title = aDecoder.decodeObject(forKey: "title") as! String
        notificationDescription = aDecoder.decodeObject(forKey: "notificationDescription") as! String
        discountId = aDecoder.decodeObject(forKey: "discountId") as! String
        discountPercent = aDecoder.decodeDouble(forKey: "discountPercent")
        discountDescription = aDecoder.decodeObject(forKey: "discountDescription")  as! String
        discountCode = aDecoder.decodeObject(forKey: "discountCode")  as! String
        discountType = aDecoder.decodeObject(forKey: "discountType") as! String
        discountExpireDate = aDecoder.decodeObject(forKey: "discountExpireDate") as! Date
        date = aDecoder.decodeObject(forKey: "date") as! Date
        super.init()
    }

    func encodeWithCoder(_ aCoder: NSCoder){
        aCoder.encode(id, forKey: "id")
        aCoder.encode(type, forKey: "type")
        aCoder.encode(brandId, forKey: "brandId")
        aCoder.encode(title, forKey: "title")
        aCoder.encode(notificationDescription, forKey: "notificationDescription")
        aCoder.encode(discountId, forKey: "discountId")
        aCoder.encode(discountPercent, forKey: "discountPercent")
        aCoder.encode(discountDescription, forKey: "discountDescription")
        aCoder.encode(discountCode, forKey: "discountCode")
        aCoder.encode(discountType, forKey: "discountType")
        aCoder.encode(discountExpireDate, forKey: "discountExpireDate")
        aCoder.encode(date, forKey: "date")
    }
}

问题出在哪里？我怎样才能解决这个问题？我在使用iOS 10.2的设备上运行应用程序

Answer 1

就我使用模拟器测试您的代码而言，更多关注 -[NSXPCEncoder _checkObject:]:

<强> This coder only encodes objects that adopt NSSecureCoding (object is of class 'TestProjectName.ServerNotification').

您可能需要将ServerNotification的标题设为：

class ServerNotification : NSObject, NSSecureCoding {

Xcode会显示一些右侧“Fix-it”的建议。

当你想要创建自己的归档器/ unarchiver时，你通常是NSCoder的子类，除此之外，这样的子类化是没用的。

userInfo中的自定义对象的UNMutableNotificationContent崩溃应用程序

1 个答案: