Question

DECLARE
   sql_stmt varchar2(400);
   cursor c1 is SELECT view_name from all_views where owner = 'owner1' AND     view_name like 'IRV_%' OR view_name like 'RD_%' order by view_name;
BEGIN
for i IN c1 loop
  sql_stmt := 'create table new_table as select * FROM owner1.view1 minus select * FROM owner2.view1';
  dbms_output.put_line(sql_stmt);
  execute immediate sql_stmt;
  for ii IN (SELECT * from new_table) loop
    dbms_output.put_line('inner loop');
  end loop;  -- for ii
  execute immediate 'drop table new_table';
  exit when c1%NOTFOUND;
end loop;  -- for i
END;

我进入脚本输出：

ORA-06550：第9行，第32栏： PL / SQL：ORA-00942：表或视图不存在

第9行是：for II IN（SELECT * from new_table）loop

提前谢谢。

好的，这是我的新代码：感谢GurV的帮助。

DECLARE
CURSOR c1
 IS
   SELECT view_name
   FROM all_views
   WHERE owner = 'DBA_A'
   AND view_name LIKE 'IRV_%'
   OR view_name LIKE 'RD_%'
   ORDER BY view_name;
BEGIN
 FOR i IN c1
 LOOP
FOR ii IN ('select * FROM DBA_A.' || i.VIEW_NAME || ' minus select * FROM DBA_B.' || i.VIEW_NAME)
LOOP
    dbms_output.put_line('inner loop');
    -- put the results from the select in the FOR ii loop in a listAgg string
    -- do stuff
 END LOOP; -- for ii
END LOOP; -- for i
END;

END LOOP产生错误; - 对于ii

PLS-00103：遇到以下任何一种情况时遇到符号“END”：

dbms_output.put_line显示生成了正确的选择。再次感谢。富

Answer 1

您的代码不知道您将动态创建表格（怎么可能？）。

通常，The PL/SQL Compiler will check your block for the following before executing it:

检查语法。
检查语义和安全性，并解析名称。
生成（并优化）字节码（a.k.a. MCode）。

它位于代码失败的第二步，因为在编译之前没有一个名为new_table的表。

我认为这里不需要动态SQL。此外，在光标上使用for循环时，不需要设置退出条件。你可以这样做：

DECLARE
  CURSOR c1
  IS
    SELECT view_name
    FROM all_views
    WHERE owner = 'owner1'
    AND view_name LIKE 'IRV_%'
    OR view_name LIKE 'RD_%'
    ORDER BY view_name;
BEGIN
  FOR i IN c1
  LOOP
    FOR ii IN (select * FROM owner1.view1 minus select * FROM owner2.view1)
    LOOP
      DBMS_OUTPUT.put_line('Hey there');
      -- do more stuff
    END LOOP; -- for ii
  END LOOP; -- for i
END;

嵌套隐式游标不存在表或视图

1 个答案: