Question

我必须为我的其他服务实现一些JUnit测试。例如，这是我的休息服务之一：

@Path("/dni-fe")
public class HelloWorld
{

    @POST
    @Path("/home")
    @Consumes(MediaType.APPLICATION_JSON)
    @Produces(MediaType.APPLICATION_JSON)

    public MachineResponse doMachineRegister(MachineBean machineBean)
    {
        MachineResponse response = new MachineResponse();
        String name = machineBean.getName();
        String country = machineBean.getCountry();
        String company = machineBean.getCompany();
        String model = machineBean.getModel();

    //make some stuff and some queries on db to populate the response object
    return response;
    }

这是我对这项服务的测试：

public class MachineResponseTest {

    private static final String BASE_URI = "http://localhost:8080/dni-fe/home"

    @Test
    public void testDevice() {

        WebResource resource = Client.create().resource(BASE_URI);
        resource.accept(MediaType.APPLICATION_JSON);

        StringBuilder sb = new StringBuilder();
        sb.append("{\"name\":\"123456\",\n");
        sb.append(" \"country\":\"Spain\",\n");
        sb.append(" \"company\":\"xxx\",\n");
        sb.append(" \"model\":\"1.10.0\"\n}");      

        MachineResponse result = resource.post(MachineResponse.class,sb.toString());
    }

测试失败，出现以下错误：

com.sun.jersey.api.client.UniformInterfaceException：POST http://localhost:8080/dni-fe/home的回复状态为415 不支持的媒体类型 com.sun.jersey.api.client.WebResource.handle（WebResource.java:686）

Answer 1

我很确定你必须使用.type(MediaType.APPLICATION_JSON)，而不是.accept(

Answer 2

您可以使用org.json.JSONObject中的简单JSONObject，并将数据作为toString传递给它。示例代码是

JSONObject address = new JSONObject();
address.put("line1", address1);
address.put("line2", address2);
address.put("city", city);
address.put("state", state);
address.put("postalCode", zip);
address.put("country", "US");
address.toString()

为休息服务实现JUnit测试

2 个答案: