Question

你可以帮我解决下面的问题吗？

php code：//

$countdate='2017-01-03';
$countsql='SELECT rucid,"databaseType","countLoggedOn","prodCount","nprodCount","countType" FROM "ru_countLog" WHERE "countLoggedOn"=$countdate';

- ＆GT;它给出了语法错误

语法错误或附近＆＃34; $＆＃34;第1行：...... untType＆＃34; FROM＆＃34; ru_countLog＆＃34; 在哪里＆＃34; countLoggedOn＆＃34; = $ countdate

Answer 1

从查询中删除内部双引号：

$countsql = "SELECT rucid, databaseType, countLoggedOn,
             prodCount, nprodCount, countType
             FROM ru_countLog
             WHERE countLoggedOn = $countdate";

请注意，此查询易受SQL注入攻击。考虑参数化$countdate。使用http://php.net/manual/en/function.pg-query-params.php ，这将成为

$countsql = 'SELECT rucid, databaseType, countLoggedOn,
         prodCount, nprodCount, countType
         FROM ru_countLog
         WHERE countLoggedOn = $1';

$result = pg_query_params($dbconn, $countsql, array($countdate));

其中$dbconn是您的数据库连接

Answer 2

也许你应该尝试这样

$countdate='2017-01-03';
$countsql='SELECT rucid,"databaseType","countLoggedOn","prodCount","nprodCount","countType" FROM "ru_countLog" WHERE "countLoggedOn"='.$countdate;

希望这个帮助

Postgres在php中查询日期变量

2 个答案: