我试图创建加密程序,但我在开始时遇到错误

时间:2017-01-04 13:18:47

标签: java java.util.scanner

User.where.not(id: [@user.id] + @user.following.ids).order('RANDOM()').first

下面的程序错误并输出以下内容

// This portion works

    import java.util.Scanner;
      class test {
    private static Scanner inp;
    public static void main(String[] args) {
        inp = new Scanner(System.in);
        System.out.println("Input Password");
        int n = inp.nextInt();
        System.out.println(n);
        if(n!=234) {
            System.out.println("Denied Acess");

        } else { 
            System.out.print("Password Accepted");
        }

1 个答案:

答案 0 :(得分:1)

import java.util.Scanner;

class Main {
    private static Scanner inp;
    public static void main(String[] args)
    {
        inp = new Scanner(System.in);
        System.out.print("Input Password: ");
        int n = inp.nextInt(); // For int
        System.out.println(n);

        if(n != 234)
        {
            System.out.println("Denied Access");
        }
        else
        {
            System.out.println("Password Accepted");
        }

        /* Scanner has already been initialized, don't create 
           a new one, use existing one, don't try and print the 
           Scanner because it is of type Scanner. */


        System.out.print("Input Text to encrypt: ");
        String m = inp.next(); // For String
        System.out.println(m);
    }
}

有关扫描仪课程的说明,请参阅此处:http://www.javatpoint.com/Scanner-class