Question

我有两个实体Person和Nursery，我和ManyToMany之间有一个JoinTable关系。我想做这2个SQL查询：

1）使用nursery_id

查找链接到托儿所的所有员工（= Person）

select p.* from person p inner join nursery_staff ns on p.id = ns.staff_id inner join nursery n on ns.nursery_id = n.id where n.id=1 and p.nursery_staff_role <> 'MANAGER';

2）找到有staff_id的员工，并确保他与托儿所的托儿所相关联

select p.* from person p inner join nursery_staff ns on p.id = ns.staff_id inner join nursery n on ns.nursery_id = n.id where n.id=2 and p.id=4 and p.nursery_staff_role <> 'MANAGER';

为此我在PersonRepository中有这两个查询：

1）

public function findAllStaffLinkedToANursery($nursery_id)
{
    $qb = $this->_em->createQueryBuilder();
    $qb->select('p')
        ->from($this->_entityName, 'p')
        ->innerJoin('VSCrmBundle:Nursery', 'n')
        ->where('n.id = :id')
        ->andWhere('p.nurseryRole <> :profession')
        ->setParameters(array('id' => $nursery_id, 'profession' => 'MANAGER'));

    return $qb->getQuery()->getResult();
}

2）

public function findOneByNurseryAndStaffId($nursery_id, $staff_id)
{
    $qb = $this->_em->createQueryBuilder();
    $qb->select('p')
        ->from($this->_entityName, 'p')
        ->innerJoin('VSCrmBundle:Nursery', 'n')
        ->where('p.id = :pid')
        ->andWhere('n.id = :nid')
        ->andWhere('p.nurseryRole <> :staffRole')
        ->setParameters(array(
            'pid' => $staff_id,
            'nid' => $nursery_id,
            'staffRole' => 'MANAGER'
        ));

    return $qb->getQuery()->getOneOrNullResult();
}

但是在这两种情况下，查询都不关心nursery_id，并且这使我的工作人员不再使用nursery_id。例如，id = 4的Person未与id = 2的托儿所链接，但此查询显示此人。

编辑： 我对dql查询有相同的结果：

 php bin/console doctrine:query:dql "select p.email from VSCrmBundle:Person p inner join VSCrmBundle:Nursery n where n.id=2 and p.nurseryRole <> 'MANAGER'"

Answer 1

也许这就是你加入幼儿园实体的方式。尝试从Person实体属性加入它，如下所示：

public function findAllStaffLinkedToANursery($nursery_id)
{
    $qb = $this->_em->createQueryBuilder();
    $qb->select('p')
        ->from($this->_entityName, 'p')
        ->innerJoin('p.nursery', 'n')
        ->where('n.id = :id')
        ->andWhere('p.nurseryRole <> :profession')
        ->setParameters(array('id' => $nursery_id, 'profession' => 'MANAGER'));

    return $qb->getQuery()->getResult();
}

这当然只有在Person具有属性苗圃并且使用Doctrine ORM映射时才有效。如果存储库扩展了Doctrine \ ORM \ EntityRepository，您也可以简化它：

public function findAllStaffLinkedToANursery($nursery_id)
{
    $qb = $this->createQueryBuilder('p');
    $qb->innerJoin('p.nursery', 'n')
        ->where('n.id = :id')
        ->andWhere('p.nurseryRole <> :profession')
        ->setParameters(array('id' => $nursery_id, 'profession' => 'MANAGER'));

    return $qb->getQuery()->getResult();
}

Answer 2

好的，感谢Sepultura我的代码有效！我点了这个：

public function findAllStaffLinkedToANursery($nursery_id)
{
    $qb = $this->createQueryBuilder('p');
    $qb->innerJoin('p.nurseries', 'n')
        ->where('n.id = :id')
        ->andWhere('p.nurseryRole <> :profession')
        ->setParameters(array('id' => $nursery_id, 'profession' => 'MANAGER'));

    return $qb->getQuery()->getResult();
}

Doctrine查询构建器提供错误的结果

2 个答案: