我想用PHP将二进制字符串转换为hexademical。二进制字符串对文本进行编码。
我试过这段代码:
echo pack('H*', base_convert('0100100001100101011011000110110001101111001000000101011101101111011100100110110001100100', 2, 16));
但它不适用于长二进制字符串。
示例:我想要' Hello World',但它正在编写' Hello X'。
如何用PHP将二进制转换为十六进制?
答案 0 :(得分:0)
如在php documentation中所述,这是因为:
由于与所使用的内部“double”或“float”类型相关的属性,base_convert()可能会丢失大数字的精度。有关更多具体信息和限制,请参阅手册中的浮点数部分。
在同一文档中,有一些关于如何解决此问题的代码示例,如下所示:
<?php
convBase('123', '0123456789', '01234567');
//Convert '123' from decimal (base10) to octal (base8).
//result: 173
convBase('70B1D707EAC2EDF4C6389F440C7294B51FFF57BB', '0123456789ABCDEF', '01');
//Convert '70B1D707EAC2EDF4C6389F440C7294B51FFF57BB' from hexadecimal (base16) to binary (base2).
//result:
//111000010110001110101110000011111101010110000101110
//110111110100110001100011100010011111010001000000110
//001110010100101001011010100011111111111110101011110
//111011
convBase('1324523453243154324542341524315432113200203012', '012345', '0123456789ABCDEF');
//Convert '1324523453243154324542341524315432113200203012' from senary (base6) to hexadecimal (base16).
//result: 1F9881BAD10454A8C23A838EF00F50
convBase('355927353784509896715106760','0123456789','Christopher');
//Convert '355927353784509896715106760' from decimal (base10) to undecimal (base11) using "Christopher" as the numbers.
//result: iihtspiphoeCrCeshhorsrrtrh
convBase('1C238Ab97132aAC84B72','0123456789aAbBcCdD', '~!@#$%^&*()');
//Convert'1C238Ab97132aAC84B72' from octodecimal (base18) using '0123456789aAbBcCdD' as the numbers to undecimal (base11) using '~!@#$%^&*()' as the numbers.
//result: !%~!!*&!~^!!&(&!~^@#@@@&
function convBase($numberInput, $fromBaseInput, $toBaseInput)
{
if ($fromBaseInput==$toBaseInput) return $numberInput;
$fromBase = str_split($fromBaseInput,1);
$toBase = str_split($toBaseInput,1);
$number = str_split($numberInput,1);
$fromLen=strlen($fromBaseInput);
$toLen=strlen($toBaseInput);
$numberLen=strlen($numberInput);
$retval='';
if ($toBaseInput == '0123456789')
{
$retval=0;
for ($i = 1;$i <= $numberLen; $i++)
$retval = bcadd($retval, bcmul(array_search($number[$i-1], $fromBase),bcpow($fromLen,$numberLen-$i)));
return $retval;
}
if ($fromBaseInput != '0123456789')
$base10=convBase($numberInput, $fromBaseInput, '0123456789');
else
$base10 = $numberInput;
if ($base10<strlen($toBaseInput))
return $toBase[$base10];
while($base10 != '0')
{
$retval = $toBase[bcmod($base10,$toLen)].$retval;
$base10 = bcdiv($base10,$toLen,0);
}
return $retval;
}
?>
然后您可以使用pack()函数回显此函数的返回值。