NSURL有特殊字符

Question

如何对此网址进行编码以显示在UIWebview中：

http://de.wikipedia.org/?search=Bevölkerungsentwicklung

我试过了：

-stringByAddingPercentEscapesUsingEncoding:NSUnicodeStringEncoding
-stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding

和

CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,
                                        (CFStringRef)mobileUrl,
                                        NULL,
                                        (CFStringRef)@"!*'();:@&=+$,/?%#[]",
                                        kCFStringEncodingUTF8);

感谢

约尔格

Answer 1

只对URL字符串的搜索部分进行编码：

// searchString is the unescaped search string, e.g., "Bevölkerungsentwicklung"

NSString *encodedSearchString = [searchString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *urlString = [NSString stringWithFormat:@"http://de.wikipedia.org/?search=%@", encodedSearchString];
NSURL *url = [NSURL URLWithString:urlString];

（另请注意，NSUTF8StringEncoding是使用的编码。）

Answer 2

使用下面的示例代码;

NSString *urlstring = [NSString stringWithFormat:@"http://de.wikipedia.org/?search=%@", searchString];
NSString *encodedString = [urlstring stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [NSURL URLWithString:encodedString];

Answer 3

我还发现，对于一些北欧角色，NSISOLatin1StringEncoding更合适。 这个给了我更好的结果

- (void) testEncoding {
    NSString * urlString = @"http://example/path/fileName_blå.pdf";
    urlString = [urlString stringByAddingPercentEscapesUsingEncoding:NSISOLatin1StringEncoding];
    NSURL * url = [NSURL URLWithString:urlString];
    NSLog(@"URL: %@", url);
}