Question

@Repository
@Transactional
@Scope("prototype")
public class EntityManagerImpl implements EntityManagerGenerator {

    @PersistenceContext(unitName = "test")
    @Qualifier("transactionManager")
    private EntityManager entityManager;

    @PersistenceContext(unitName = "test1")
    @Qualifier("transactionManager1")
    private EntityManager entityManager2;

    @Override
    public EntityManager getEntityManager(String userType) {

        if(userType.equals("test")){
            return entityManager2;
        }else{
            return entityManager;
        }
    }

这里如何动态地使用entitymanager明智的事务管理器。我共享了我的xml配置文件。

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"     xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee"
 xmlns:cache="http://www.springframework.org/schema/cache"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
     http://www.springframework.org/schema/cache http://www.springframework.org/schema/cache/spring-cache-3.2.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
    http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
    http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd"
xmlns:p="http://www.springframework.org/schema/p"   xmlns:tx="http://www.springframework.org/schema/tx">

<bean id="jpaVendorAdapter"
    class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
    <property name="database" value="ORACLE" />
    <property name="showSql" value="false" />
</bean>

<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"
    p:entityManagerFactory-ref="entityManagerFactory" />

 <bean id="entityManagerFactory2"
    class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="dataSource" ref="test1.ds" />
     <property name="persistenceUnitName" value="test1" />        
    <property name="jpaVendorAdapter" ref="jpaVendorAdapterFC" />
    <property name="persistenceXmlLocation" value="classpath:jpa-persistence.xml" />
</bean>

<bean id="jpaVendorAdapterFC"
    class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
    <property name="database" value="ORACLE" />
    <property name="showSql" value="false" />
</bean>

  <bean id="transactionManager1" class="org.springframework.orm.jpa.JpaTransactionManager"
    p:entityManagerFactory-ref="entityManagerFactory2" />  



<bean id="cacheManager" class="org.springframework.cache.ehcache.EhCacheCacheManager" p:cache-manager-ref="ehcache" />
<bean id="ehcache" class="org.springframework.cache.ehcache.EhCacheManagerFactoryBean" p:configLocation="classpath:ehcache.xml" />

<!-- Transaction manager for a single JPA EntityManagerFactory (alternative 
    to JTA) -->



<!-- Activates various annotations to be detected in bean classes: Spring's 
    @Required and @Autowired, as well as JSR 250's @PostConstruct, @PreDestroy 
    and @Resource (if available) and JPA's @PersistenceContext and @PersistenceUnit 
    (if available). -->

<context:component-scan base-package="com.wmi.test" annotation-config="true"
scope-resolver="org.springframework.context.annotation.Jsr330ScopeMetadataResolver"/>

<!-- Instruct Spring to perform declarative transaction management automatically 
    on annotated classes. -->
<tx:annotation-driven />
<cache:annotation-driven />

那么我如何根据我的配置将单个事务管理器用于多个数据源这里我们用作事务管理器作为@Transactional注释

多个实体管理员的单个jpa事务管理器

0 个答案: