Question

我希望用户为int temp1和int temp2分配一个值。但是，编译器说我需要初始化两个变量之一（temp2）。

为什么只要求我初始化temp2而不是temp1？当我为temp2分配一个值时，程序会忽略用户输入的任何值。

我的代码是不是很草率，如果有的话，我有办法解决这个问题吗？

（我已经包含了整个程序以防它相关，但我收到的错误是在inputDetails（）函数中。）

#include <iostream>
using namespace std;

//Prototype

void inputDetails(int* n1, int* n2);
void outputDetails(int num1, int num2, int* pNum, int* n1, int* n2, int** ppNum);

//Functions

int main()
{
int num1;
//num1 pointer
int* n1 = &num1;

int num2;
//num2 pointer
int* n2 = &num2;

//get pNum to point at num1
int* pNum;
pNum = new int;
*pNum = num1;

//pointer to pNum
int** ppNum = &pNum;

//call functions
inputDetails(n1, n2);
outputDetails(num1, num2, pNum, n1, n2, ppNum);

//change pNum to point at num2
delete pNum;
pNum = new int;
*pNum = num2;

//call function again
outputDetails(num1, num2, pNum, n1, n2, ppNum);
delete pNum;

system("PAUSE");
return 0;
}

void inputDetails(int* n1, int* n2)
{
int temp1, temp2;
cout << "Input two numbers" << endl;
cin >> temp1, temp2;
*n1 = temp1;
*n2 = temp2;
}

void outputDetails(int num1, int num2, int* pNum, int* n1, int* n2, int** ppNum)
{
cout << "The value of num1 is: " << num1 << endl;
cout << "The address of num1 is: " << n1 << endl;
cout << "The value of num2 is: " << num2 << endl;
cout << "The address of num2 is: " << n2 << endl;
cout << "The value of pNum is: " << pNum << endl;
cout << "The dereferenced value of pNum is: " << *pNum << endl;
cout << "The address of pNum is: " << ppNum << endl;
}

Answer 1

为什么只要求我初始化temp2而不是temp1？

以下内容并不符合您的想法（它无意中使用了comma operator）：

cin >> temp1, temp2;

要从cin读取两个值，请使用：

cin >> temp1 >> temp2;

为什么我需要在用户为其赋值之前初始化此变量？

1 个答案: