我需要一个用于字节校正的控制台应用程序,使用汉明算法。有人可以帮我解决这个问题吗?
输入单词例如:11100100
答案 0 :(得分:1)
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Collections;
namespace Bits
{
class Program
{
static void Main(string[] args)
{
string NrBinary;
int pp, Key, number;
double x, y;
Console.WriteLine("Give binary value till 8 bit: ");
NrBinary = Console.ReadLine();
if (NrBinary.Length <= 8)
{
if (NrBinary.Length == 1) NrBinary = "0000000" + NrBinary;
if (NrBinary.Length == 2) NrBinary = "000000" + NrBinary;
if (NrBinary.Length == 3) NrBinary = "00000" + NrBinary;
if (NrBinary.Length == 4) NrBinary = "0000" + NrBinary;
if (NrBinary.Length == 5) NrBinary = "000" + NrBinary;
if (NrBinary.Length == 6) NrBinary = "00" + NrBinary;
if (NrBinary.Length == 7) NrBinary = "0" + NrBinary;
pp = NrBinary.Length;
number = Convert.ToInt32(NrBinary);
Console.WriteLine("PP = " + pp);
for (Key = 0; Key < pp; ++Key)
{
x = Math.Pow(2, Key) - 1;
y = pp + Key;
if (x >= y)
{
goto Mess;
}
}
Mess:
Console.WriteLine("Controled bit needed Key = " + Key + "\n");
int[] parity = new int[pp];
int[] DI = new int[pp];
int[] CI = new int[Key];
DI[0] = number % 10;
DI[1] = (number / 10) % 10;
DI[2] = (number / 100) % 10;
DI[3] = (number / 1000) % 10;
DI[4] = (number / 10000) % 10;
DI[5] = (number / 100000) % 10;
DI[6] = (number / 1000000) % 10;
DI[7] = (number / 10000000) % 10;
CI[0] = DI[0] ^ DI[1] ^ DI[3] ^ DI[4] ^ DI[6];
CI[1] = DI[0] ^ DI[2] ^ DI[3] ^ DI[5] ^ DI[6];
CI[2] = DI[1] ^ DI[2] ^ DI[3] ^ DI[7];
CI[3] = DI[4] ^ DI[5] ^ DI[6] ^ DI[7];
Console.WriteLine("\n = " + CI[0] + "" + CI[1] + "" + CI[2] + "" + CI[3] + "\n");
Console.Write("Bit with Hamming code: ");
Console.WriteLine(DI[7] + "" + DI[6] + "" + DI[5] + "" + DI[4] + "" + CI[3] + "" + DI[3]
+ "" + DI[2] + "" + DI[1] + "" + CI[2] + "" + DI[0] + "" + CI[1] + "" + CI[0]);
}
else
{
Console.WriteLine("\n\n 8 bit character maximaly:)");
}
}
}
}
答案 1 :(得分:0)
假设这是家庭作业,这里是pointer to the general algorithm。自己动手,发布你尝试过的内容以及你遇到的具体问题,人们可能会帮助你。