Question

我有一张包含以下数据的表格

SQL> select * from mate2;

      A_CD       S_ID       E_CD S_E   S_NE  E_IND
---------- ---------- ---------- ----- ----- -
       100          1          3 A     J     Y
       100          1          3 B     A     N
       100          1          3 A     D

       200          2          3 A     C     Y
       200          2          3 D     C

       300          3          3 B     N     Y
       300          3          3 N     N

我需要通过A_CD和（S_E，S_NE）将不同的S_E，S_NE组计为具有以下条件的字母代码：

当（E_CD = 3 AND E_IND = N）
当E_CD = 3且E_IND = Y
当E_CD = 3时，取S_NE的值并且E_IND为空并且DISPLAY E_IND为N
当E_CD = 3时，取S_E的值并且E_IND为空并且DISPLAY E_IND为Y

输出应如下所示。 L_C是S_E，S_NE

A_CD L_C COUNT E_IND
---- --- ----- -----
100   A    3    Y
100   D    1    N

200   A    1    Y
200   D    1    Y
200   C    1    N

300   B    1    Y
300   N    1    Y
300   N    1    N

下面的样本表创建和数据用于测试

create table Mate2(a_cd number(5),S_ID NUMBER, E_CD number(10), S_E varchar2(5), S_NE varchar2(5), E_IND CHAR(1 byte));


insert into Mate2 values (100,1,3,'A','J','Y');
insert into Mate2 values (100,1,3,'B','A','N');
insert into Mate2(a_cd,S_ID,E_CD,S_E,S_NE) values (100,1,3,'A','D');
insert into Mate2 values (200,2,3,'A','C','Y');
insert into Mate2(a_cd,S_ID,E_CD,S_E,S_NE) values (200,2,3,'D','C');
insert into Mate2 values (300,3,3,'B','N','Y');
insert into Mate2(a_cd,S_ID,E_CD,S_E,S_NE) values (300,3,3,'N','N');

Answer 1

您必须首先拆分E_IND，然后才能简单

WITH data1 as (
    SELECT A_CD, E_CD, S_E, S_NE,
           CASE when E_CD = 3 and E_IND is null then 'N'
                else E_IND 
           END as E_IND
    FROM mate2

    UNION ALL

    SELECT A_CD, E_CD, S_E, S_NE, 'Y' E_IND
    FROM mate2
    WHERE E_CD = 3 and E_IND is null
)
SELECT A_CD, L_C, COUNT(*) as COUNT, E_IND FROM (
    SELECT A_CD,
           CASE when E_CD = 3 and E_IND = 'N' then S_NE
                when E_CD = 3 and E_IND = 'Y' then S_E
                else 'what_to_do_with_these'
           END as L_C,
           E_IND
    FROM data1
)
GROUP BY A_CD, L_C, E_IND
order by A_CD, E_IND desc, L_C;

我在E_CD = 2添加了一条额外的记录，以显示没有给出指令的情况。我想您的环境中存在此类数据，条件包括E_CD

insert into Mate2(a_cd,S_ID,E_CD,S_E,S_NE) values (100,1,2,'X','F');

输出

A_CD    L_C COUNT   E_IND
----    --- -----   -----
100 what_to_do_with_these   1    - 
100     A   2       Y
100     A   1       N
100     D   1       N
200     A   1       Y
200     D   1       Y
200     C   1       N
300     B   1       Y
300     N   1       Y
300     N   1       N

遵循您的规则，给定的结果行100 A 3 Y不正确，因为A来自E_IND = N

Answer 2

不确定这是否是您要找的，似乎您的总记录数与您提供的所需输出不匹配，否则请尝试以下内容：

SELECT ABC.a_cd,ABC.L_C,COUNT(*)as COUNT,ABC.E_IND FROM (
select A_CD, case when E_CD = 3 and E_IND  = 'N' then S_NE
                  when E_CD = 3 and E_IND = 'Y' then S_E 
                  when E_CD = 3 and E_IND is null then S_NE
                  when E_CD = 3 and E_IND is null then S_E
                  end as L_C,

             case when E_CD = 3 and E_IND is null then 'N'
                  when E_CD = 3 and E_IND is not null then 'Y'
                  else E_IND 
                  end as E_IND

FROM Mate2) as ABC
GROUP BY ABC.a_cd, ABC.L_C,ABC.E_IND

如何根据其他列值显示值的计数

2 个答案: